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Gwar [14]
3 years ago
5

How to do this ? Don’t understand it

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
X=y+3
<span>-5x-4y=<span>30
-------------------
Substitute y + 3 for x in </span></span>-5x-4y=30
<span><span>-5<span>(y+3)-</span></span>4y</span>=<span>30
</span>-9y-15=<span>30
</span>----------------------------
Add 15 to each side
<span><span>-9y-15</span>+15</span>=<span>30+<span>15
-9y = 45
</span></span>-----------------------------------
Divide each side by -9
-9y ÷ -9 = 45 ÷ -9
y = -5
Now we solve for x
====================================================================
Substitute -5 for y in x = y + 3
x=-<span><span>5</span>+<span>3
</span></span>x = -2
----------------------
(-2,-5) is your answer


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Answer:

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If we get the answer of any question where the found probability is greater than 1 the answer is wrong because probability is not greater than 1.

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Step-by-step explanation:

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MAXImum [283]

Answer:

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Step-by-step explanation:

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Answer:

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

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So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation  

X_{1}=507 represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

n_{1}=32601 sample elected from arizona

\hat p_{1}=\frac{507}{32601} =0.0156 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

p_{2}=\frac{1}{88}= 0.0114 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD)  in the nation

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

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Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

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Statistical decision

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Since is a one right sided test the p value would be:  

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

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