Answer:
Step-by-step explanation:
Given the approximate demand function of night drink expressed as;
p^2+200q^2=177,
p is the price (in dollars) and;
q is the quantity demanded (in thousands).
Given
p = $7
q = 800
Required
dq/dp
Differentiating the function implicitly with respect to p shown;
2p + 400d dq/dp = 0
400q dq/dp = -2p
200qdq/dp = -p
dq/dp = -p/100q
substitute p and q into the resulting equation;
dq/dp = -7/100(800)
dq/dp = -7/80000
dq/dp = -0.0000875
This means that the rate of change of quantity demanded with respect to the price is -0.0000875
2y^2-7y+6= 2y^2-4y-3y+6
=2y(y-2)-3(y-2)
=(2y-3)(y-2)
Therefore
y=3/2 or y=2
<span>1. </span><span>Given equation = 2 thousands 7
tens / 10.
From this given equation, give the unit form and the standard form
Unit form is the expression where you replace the number with its place values.
=> 2 thousands and 7 tens divided by 1 tens.
=> 2 hundreds 7 ones – answer in unit form
Standard form is the expression which uses numbers and operators to express an
equation.
=> 2 070 / 10
=> 207 – answer in standard form</span>
Yes, but what is the question
Answer:
a = 5
Step-by-step explanation:
Hello, please consider the following.

So, a = 5.
Thank you.