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2 years ago

Use the Distributive Property to determine which of the following statements is equivalent to 5(6 – 2).

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

7 0

Answer:

D 30-2

Step-by-step explanation:

5 x 6 = 30 - 5 x 2 = 28

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He would have drank 22.4 litres of water in 14 days

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2 years ago

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The slope of the line whose equation is given

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2 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

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2 years ago

Anyone know the answer ? Please is it a function or relation?

levacccp [35]

Answer: i think its a function

Step-by-step explanation:

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2 years ago

Suppose that you are a member of this arbitration panel. Construct a 95% confidence interval for the true mean return of the inv

lisabon 2012 [21]

Answer: Margin of Error = 1.944

Lower Bound = 3.052

Explanation:-

Attached below is a file for monthly Rate of return. Used an excel sheet to determine the confidence interval which seems relatively easier as compared to manual computation. The range below (A2:A40) shows the monthly

Functions used : Standard Deviation as= STDEV (A2:A40)

Sample Mean = AVERAGE(A2:A40)

Margin of Error = CONFIDENCE.T(D4,D5,D2)

Lower Bound Interval = D6-D7 = -3.052

3 0

3 years ago