Given:
![\text{ Dimension = 3}\times5](https://tex.z-dn.net/?f=%5Ctext%7B%20Dimension%20%3D%203%7D%5Ctimes5)
Sol:
Area of picture is:
![\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D%5Ctext%7B%20length%7D%5Ctimes%5Ctext%7B%20Width%7D%20%5C%5C%20%20%5C%5C%20%3D15%20%5Cend%7Bgathered%7D)
If the cost $10 per square inch then price of 15 square inch is:
![\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D15%5Ctimes10%20%5C%5C%20%20%5C%5C%20%3D150%20%5Cend%7Bgathered%7D)
If the quadruple of dimension that mean:
![\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20l%20ength%20%3D%204%20length%7D%20%5C%5C%20%20%5C%5C%20Width%5Ctext%7B%20%3D%204%20width%7D%20%5Cend%7Bgathered%7D)
So area is:
![\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D4%5Ctext%7B%20length%7D%5Ctimes4%5Ctext%7B%20Width%7D%20%5C%5C%20%20%5C%5C%20A%3D4%2815%29%20%5C%5C%20%20%5C%5C%20A%3D60%20%5Cend%7Bgathered%7D)
So price is:
Answer:
x^4 - 2x^3 - 29x^2 - 42x
Step-by-step explanation:
Equal all the zeros to x then move them over.
x=7,x=-3,x=0,x=-2
x-7,x+3,x+0,x+2
Then multiply each factor
(x-7)(x+3)(x)(x+2)
x^4 - 2x^3 - 29x^2 - 42x
Answer:
(-4,-4)
Step-by-step explanation: