$(2^3x^2 - 3) - 2 = 0 \\ \\ Factoring: \ 8x^2-5 \\ \\ 8x^2 - 5 = 0 \\ \\ Add \ 5 \ to \ both \ sides \ of \ the \ equation : \\ \\ 
 8x^2 = 5 \\ \\ Divide \ both \ sides \ of \ the \ equation \ by \ 8: \\ \\ 
 x^2 = \frac{5}{8} = 0.625 \\ \\ \boxed{ x =\pm \sqrt 5/8}$

Your answer: Option A

7 0

4 years ago

Answer quick please i will mark brainliest:

SOVA2 [1]

Look at the attached picture

Hope it will help you....

Good luck on your assignment

8 0

3 years ago

Determine whether the series is convergent or divergent (ln(n))/(n^2)

yawa3891 [41]

Letting n approach infinity results in the undefined "infinity over infinity."

Differentiate numerator and denominator separately, obtaining

1/n

(limit as n approaches infinity of) ------------- = 0. Series is convergent.

6 0

4 years ago