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3 years ago

Megan’s room is expanded so the width is 150% of 3 meters. What is the new width?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

<h3>Answer: 4.5 meters</h3>

Work Shown:

The keyword "of" means "multiply".

150% = 150/100 = 1.5

150% of 3 = 1.5*3 = 4.5

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Sam and Terry each have marbles Sam has five more than twice number that Terry has If Terry has 8 marbles how many does Sam have

Advocard [28]

S =2T+5

T=8

S = 2*8 +5

S = 16+5

S = 21

Sam has 21 marbles

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3 years ago

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Kris finds a bag of glass beads on sale for $10.77 and a pattern book on sale for $8.00.

frez [133]

Is there information we are missing to this problem? What I believe we are missing is the amount of money she starts off with and the other three items she finds.

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3 years ago

Will ran 3.23 km the first week and 4.15 km the second week. Chuck ran 8.75 km in two weeks.

Lostsunrise [7]

Will ran 3.23 + 4.15 = 7.38 in those 2 weeks, which rounds up to 7.4 km.
Chuck ran 8.75, which rounds to 8.8.

8.8 - 7.4 = 1.4 km
This means that Chuck ran 1.4 km more than Will, therefore the answer is D. about 1.4 km.

Hope this helps :)

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3 years ago

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Researchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a rando

inysia [295]

Answer:

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

D) The data come from a Population that is Normally distributed

F) the samples are independent

c)

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Step-by-step explanation:

Given data Among the 530 males surveyed, 175 responded "Yes

The sample proportion of males

$p_{m} ^{-} = \frac{x}{n} = \frac{175}{530} = 0.3301$

The sample proportion of 575 Females surveyed, 218 responded "Yes

$p_{fem} ^{-} = \frac{x}{n} = \frac{218}{575} = 0.3791$

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

The data come from a Population that is normally distributed.

The two samples are independent

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

We will use two samples Z - hypothesis test

$Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{p_{m}(1-p_{m}) }{n_{m} }+\frac{p_{fem} (1-p_{fem} )}{n_{fem} } }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301) }{530 }+\frac{0.3791(1-0.3791)}{575} }$

$Se(p_{m} ^{-} - p^{-} _{fem} ) = \sqrt{0.000826} = 0.0287$

The test statistic

$Z = \frac{0.3301-0.3791}{0.02875}$

Z = -1.7043

|Z| = |-1.7043|

The tabulated value Z₀.₉₅ = 1.96

The calculated Z= 1.7043 < 1.96 at 0.05 level of significance

The null hypothesis is accepted

Conclusion:-

The evidence suggest not a higher proportion of females are annoyed by this behavior

4 0

3 years ago

In a right triangle where one of the angles measure 30° what is the ratio of the length of the side opposite the 30°angle to the

kifflom [539]

Answer:

The ratio of the length of the side opposite the 30°angle to the length of the side opposite the 90°angle is 1:2.

Step-by-step explanation:

Consider ABC, With 90° angle at B and 30° angle at C.

To find: AB:AC=?

Solution:

AB = perpendicular of the right angled triangle

AC = Hypotenuse of the triangle

$Sin\theta =\frac{Perpendicular}{Hypotenuse}$

$sin\theta =Sin 30^o=\frac{AB}{AC},(Sin 30^o=\frac{1}{2})$

$\frac{1}{2}=\frac{AB}{AC}$

The ratio of the sides ,AB:AC = 1:2.

Hence,the ratio of the length of the side opposite the 30°angle to the length of the side opposite the 90°angle is 1:2.

3 0

4 years ago