Answer:
Step-by-step explanation
using the rules of exponents, it would be ÷
so then take away 27 from 10 and get -17 meaning that the answer would be A or
What are the zeros of 3x²(x+π)³(x-4)²
1 answer:
Hi again!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!
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Answer: x =
Step-by-step explanation: Multiply -36 and 163/9 to get -652. Add 652 to both sides then add 130 and 652 to get 782. Divide both sides by -12 then reduce the fraction 782/-12 to lowest terms by extracting and canceling out 2. The system is now solved.
Answer:
The answer is <em>1</em>.
Step-by-step explanation:
Given the expression:
To find:
The expression without absolute value.
Solution:
First of all, let us learn about the absolute value function:
i.e. value is x if x is positive
value is -x if x is negative
Here the given expression contains two absolute value functions:
and
Using the definition of absolute value function as per above definition.
Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6
So, given expression will be equivalent to :
So, the expression is equivalent to <em>1</em>.