Answer:
t = (A/sx) - r
Step-by-step explanation:
Solve for t like this:
![A = s(t+r)x\\A = sx(t+r)\\\\\frac{A}{sx} = t+r\\\frac{A}{sx} - r = t\\t= \frac{A}{sx} - r](https://tex.z-dn.net/?f=A%20%3D%20s%28t%2Br%29x%5C%5CA%20%3D%20sx%28t%2Br%29%5C%5C%5C%5C%5Cfrac%7BA%7D%7Bsx%7D%20%3D%20t%2Br%5C%5C%5Cfrac%7BA%7D%7Bsx%7D%20-%20r%20%3D%20t%5C%5Ct%3D%20%5Cfrac%7BA%7D%7Bsx%7D%20-%20r)
Answer:
m∠P=140°
Step-by-step explanation:
Given:
∠P and ∠Q are supplementary angles.
The measure of angle P is five less than four times the measure of angle Q.
To find m∠P
Solution:
The measure of angle P can be given as:
A) ![m\angle P=4(m\angle Q-5)](https://tex.z-dn.net/?f=m%5Cangle%20P%3D4%28m%5Cangle%20Q-5%29)
And
B)
[Definition of supplementary angles]
Substituting equation A into B.
![4(m\angle Q-5)+ m\angle Q=180](https://tex.z-dn.net/?f=4%28m%5Cangle%20Q-5%29%2B%20m%5Cangle%20Q%3D180)
Solving for ![m\angle Q](https://tex.z-dn.net/?f=m%5Cangle%20Q)
Using distribution:
![4m\angle Q-20+ m\angle Q=180](https://tex.z-dn.net/?f=4m%5Cangle%20Q-20%2B%20m%5Cangle%20Q%3D180)
Simplifying by combining like terms.
![5m\angle Q-20=180](https://tex.z-dn.net/?f=5m%5Cangle%20Q-20%3D180)
Adding 20 to both sides.
![5m\angle Q-20+20=180+20](https://tex.z-dn.net/?f=5m%5Cangle%20Q-20%2B20%3D180%2B20)
![5m\angle Q=200](https://tex.z-dn.net/?f=5m%5Cangle%20Q%3D200)
Dividing both sides by 5.
![\frac{5m\angle Q}{5}=\frac{200}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5m%5Cangle%20Q%7D%7B5%7D%3D%5Cfrac%7B200%7D%7B5%7D)
![m\angle Q=40](https://tex.z-dn.net/?f=m%5Cangle%20Q%3D40)
Substituting
in equation B.
![m\angle P+ 40=180](https://tex.z-dn.net/?f=m%5Cangle%20P%2B%2040%3D180)
Subtracting both sides by 40.
![m\angle P+ 40-40=180-40](https://tex.z-dn.net/?f=m%5Cangle%20P%2B%2040-40%3D180-40)
![m\angle P=140](https://tex.z-dn.net/?f=m%5Cangle%20P%3D140)
Thus, we have:
m∠P=140° (Answer)
Which question? There are 2 different questions here .
A 40 x 110 rectangle has an area of 4400 sq. ft.
The horse has a 14 ft lead. That makes 14 ft. the radius that the horse can cover.
The formula for the area of a circle is r^2 * PI ( radius squared * 3.14 ).
So the horse can't get to 4400 - ( 14 * 14 * 3.14 ) sq. ft.