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IRINA_888 [86]
3 years ago
5

Write with explain. ​

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer: The acute angle between diagonals is 50

Step-by-step explanation:

Red angle = 50 because An exterior angle of a triangle is equal to the sum of the opposite interior angles (pink angles).

Alternatively:

Green angle is 130 by sum of interior angles of a triangle.

Red angle is 50 by Adjacent angles

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
An invoice is dated January 17 with terms of 8/10 , 6/20 , 4/30 , n/40 . find the three final discount dates and the net payment
IRISSAK [1]

Invoice Date = January 17

• First terms:

8/10 and n/40

This means the final discount can be availed "10" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 10 days = January 27

Final Discount Date = Jan 27

The net payment date will be "n/40", which is 40 days from invoice date, thus

Net payment date will be:

Jan 17 - Jan 31 = 14 days

Feb 1 - Feb 26 = 26 days

------------------------------------

40 days

Payment Date = Feb 26

• Second terms:

6/20 and n/40

This means the final discount can be availed "20" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 6

Final Discount Date = Feb 6

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

• Third terms:

4/30 and n/40

This means the final discount can be availed "30" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 16

Final Discount Date = Feb 16

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

6 0
1 year ago
Arrange the hyperbolas in increasing order of the horizontal widths of their asymptote rectangles.
almond37 [142]

The  increasing order of the horizontal widths of their asymptote rectangles is dependent on the values gotten from  y = ± x.

<h3>What is a Hyperbola?</h3>

This is defined as a two-branched open curve formed by the intersection of a plane perpendicular to the bases of a double cone.

The rectangular hyperbola has two asymptotes which are defined as y = ± x in this scenario.

Read more about Hyperbola here brainly.com/question/3351710

#SPJ1

8 0
1 year ago
What is the best estimate of 48%of 60
nadezda [96]
Correct answer is 36%
5 0
3 years ago
Read 2 more answers
Suppose you invest $20,000 at the age of 40, and agree to start receiving
prohojiy [21]

Answer:

a

Step-by-step explanation:

just tryna get brainley points

6 0
3 years ago
Read 2 more answers
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