Using the Pythagorean theorem:
x^2 + (x-2)^2 = (√20)^2
Simplify the right side:
x^2 + (x-2)^2 = 20
Subtract 20 from both sides:
x^2 + (x-2)^2 - 20 = 0
Factor:
(x-4)(x+2) = 0
Solve for each x:
x = 4 and x = -2
The side cant be a negative value, so the answer would be x = 4
The answer is B.
Answer: No unless the fbi cathches up to you mr.gieco
Step-by-step explanation:
<h3>
Answer: Choice C</h3>
{x | x < -12 or x > -6}
=========================================================
Explanation:
Let's solve the first inequality for x.
(-2/3)x > 8
-2x > 8*3
-2x > 24
x < 24/(-2)
x < -12
The inequality sign flips when we divide both sides by a negative value.
Let's do the same for the second inequality.
(-2/3)x < 4
-2x < 4*3
-2x < 12
x > 12/(-2)
x > -6
The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.
Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.
<span>If two terms in a binomial are perfect squares separated by subtraction, then you canfactor them. To factor the difference of two perfect squares, remember this rule: if subtraction separates two squared terms, then the sum and the difference of the twosquare roots factor the binomial.</span>
I'm not too sure about this one but if you find 3% of $200 you get 6 and if you multiply that by 2 ( for the 2 years ) you'll get ( A $12 )