Answer:
Amount of salt dissolved in each liter of seawater = 40 g
Explanation:
According to Archimedes principle, a body will float in a fluid if the upthrust experienced by a body is equal to the to the weight of the body.
Also, the volume of seawater displaced equals the volume of freshwater in the cup.
From the above principle, since the freshwater and cup floats in the seawater, their combined weight equals the upthrust.
Therefore, mass of equal volume of displaced seawater = mass of freshwater + mass of cup
Mass of freshwater = density of freshwater * volume
density of freshwater = 1 g/mL; volume = 375 mL
mass of freshwater = 375 mL * 1 g/mL = 375 g
mass of seawater = 375 + 15 = 390 g
mass of salt in 375 mL seawater = mass of seawater - mass of freshwater
mass of salt = (390 - 375) g = 15 g
Since 15 g of salt are dissolved in 375 mL seawater, mass of salt in 1 L of seawater =(1000 mL/ 375) * 15g = 40 g
Therefore, amount of salt dissolved in each liter of seawater = 40 g
