Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1
Answer:
Choose the least electronegative atom other than H.
Explanation:
A Lewis structure consists of <em>terminal atoms</em> and one or more <em>central atoms</em>.
H can be <em>only a terminal atom</em> because it can form only one bond.
So the central atom must be either C or O.
The central atom is the less electronegative atom: C.
So, start the Lewis structure with a central C atom.
Then attach an O atom to get C-O.
Finally, attach the H atoms.
The condensed formula often gives you a clue where they go.
The formula CH₃OH implies that there are 3 H atoms on C and one on O.
The connectivity of the atoms is then as in the diagram below.
Answer:
Back away from the situation and tell the supervisor/teacher
Answer:
The concentration would be; 0.0038 μgmL
Explanation:
Half life, t1/2 = 68 minutes
Initial Conc. [A]o = 0.12/μgmL
Final Conc [A] = ?
Time. k = 340 minutes
ln[A] = ln[A]o - kt
t1/2 = ln2 / k
k = 0.693 / t1/2 = 0.693 / 68 = 0.01019
ln[A] = ln (0.12) - 0.01019 (340)
ln[A] = -2.1203 -3.4646
ln[A] = -5.5849
[A] = 0.00375 ≈ 0.0038 μgmL
