Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
5
Step-by-step explanation:
You first start by finding the acceleration of the problem.
a=f/m
Which this case is 45.
The question is asking " How many times greater must it be than A?"
You then divide
45/9
Your final answer is 5.
Answer: 2
(The slope is always the coefficient of the independent variable, in this case x . The slope is therefore 2.)
Answer:
The answer is (x+y)^3
Step-by-step explanation:
using the division/subtraction law of indices
In indices division is equal to subtraction on powers
(x+y)^5 ÷ (x+y)^2
=(x+y)^5-2
=(x+y)^3
