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iogann1982 [59]

3 years ago

9

Which sphere has a volume of 0.288Pi in.3? A sphere with radius 0.4 inches. A sphere with radius 0.5 inches. A sphere with radiu

s 0.6 inches. A sphere with radius 0.7 inches.

2 answers:

worty [1.4K]3 years ago

5 0

<em>C. A sphere with radius 0.6 inches.</em>

<u><em>Here is why:</em></u>

The equation for the volume of a sphere is:

$V=\frac{4}{3} \pi r^3$

We can plug in and solve.

$V=\frac{4}{3}*\pi *0.6*0.6*0.6$

We will multiply everything but leave the 3 to divide later.

So...

$4*\pi *0.6*0.6*0.6=0.864\pi$

Divide by 3.

$0.864\pi /3=$

0.288π

gulaghasi [49]3 years ago

3 0

Answer:

C. A sphere with radius 0.6 inches

Step-by-step explanation:

Volume = (4/3) pi × r³

0.288pi = (4/3)pi × r³

r³ = 0.216

r = 0.6

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A company manufactirung snowboards has fixed costs of $200 per day and total cost of $3800 per day at a daily output of 20 board

polet [3.4K]

A. The cost per 20 boards is 3800. so each board costs 3800/20 or $190. So the cost equation is C(x) = 200 + 190x

B. Divide the cost function by x. C(x)/x = 200/x + 190

C. The graph will be a curve that starts at (1,390) and curves down and to the right. Your last point will be at (30, 200/30+190) Your asymptote will be the horizontal line at 190 because as x tends to infinity, the term 200/x goes to zero. (There is also a vertical asymptote at x = 0 because you can't divide by zero, but your graph won't include x=0)

D. The average cost tends to 190 which was your horizontal asymptote.

7 0

3 years ago

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

(Area of Composite Figures)Help me pls.

oksian1 [2.3K]

Answer:

69 centimeters squared

Step-by-step explanation:

First, find the area of the big square = 11cm * 4cm = 44cm

Next, find the area of the leftover square = 5cm * 5cm =25cm

Add them together to get 69 centimeters squared

Hopefully this helps - let me know if you have any questions!

6 0

2 years ago

Read 2 more answers

I need help on this quick

Pachacha [2.7K]

Answer:

The hypotenuse to the nearest tenth is 8.1

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

Let a be the x leg and b be the y leg

a = 7 units

b= 4 units

7^2 + 4^2 = c^2

49+ 16 = c^2

65 = c^2

Take the square root of each side

sqrt(65) = sqrt(c^2)

8.062257748 =c

To the nearest tenth

8.1 =c

7 0

3 years ago

Which does not represent an integer?

miv72 [106K]

Answer:

The answer is D

Step-by-step explanation:

Let's see all choices in detail

A . 0 it is correct because 0 is an integer

B .It seems like rational number but it is not simplified yet so -18 \ 2= -9

C .

$\sqrt{9} = 3 \: so \: it \: is \: also \: integer$

D . 4\5 it is decimal so it is rational number not integer

I hope u like it

4 0

3 years ago