1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AysviL [449]
3 years ago
8

Define ductile.........?​

Chemistry
2 answers:
wel3 years ago
3 0

Answer:

able to drawn on thin wire.........

daser333 [38]3 years ago
3 0

Answer:

being able to hammer out thin

Explanation:

some examples are jf you were to get a piece of wire and hammer it,if would become flat.

hope that helps

You might be interested in
In the Energy and Specific Heat lab, how should the water bath be stabilized over the heat source? Select one:
Reika [66]

Answer:

c

Explanation:

5 0
3 years ago
Read 2 more answers
Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
Ostrovityanka [42]

Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

6 0
3 years ago
Write the electron configuration for the elements whose atomic numbers are the following:
andreev551 [17]

Answer:

3= Lithium (Li) = [He] 2s1

6= Carbon (C) = [He] 2s2 2p2

8=Oxygen (O)= [He] 2s2 2p4

13=Aluminium (Al)= [Ne] 3s2 3p1

U 2 can help me by marking as brainliest.........

6 0
2 years ago
PLEASE HELP IT DUE TODAY WILL GIVE 100 BRAINLY POINTS AND BRAINLYEST
inessss [21]

Answer:

1. The energy intensity from the ruler going through the air

2. This one is pretty simple, you can add or take away things. This question is just asking you to list sounds from high pitch, to lowest pitch. Here are mine:

Timer

Microwave

Mouse clicking

Dog Barking

Voice

Typing

Knocking on door

Breathing

Foot Steps

Explanation:

4 0
2 years ago
!!!PLEASE HELP!!!!
Lynna [10]

Answer: B

Explanation: molarity = concentration c= n/V = 0.5 mol/ 0.05 l = 10 mol/l

4 0
2 years ago
Other questions:
  • Calculate the work (kJ) done during a reaction in which the internal volume expands from 28 L to 51 L against an outside pressur
    5·1 answer
  • Which of the following is true for all chemical reactions
    8·1 answer
  • Under what circumstances will a scientific theory be changed or discarded? A. New experimental evidence is not compatible with t
    11·2 answers
  • Assume that you have developed a tracer with first-order kinetics and k = 0.1 s − 1 . For any given mass, how long will it take
    15·1 answer
  • Magnesium is able to ____ copper, and copper is able to ____ magnesium.
    10·1 answer
  • A chemical reaction was used to produce 2.54 moles of copper(II) bicarbonate, Cu(HCO3)2. What mass of copper(II) bicarbonate was
    10·1 answer
  • How many grams of NaN3 are required to produce 283 L of nitrogen gas about the size of an automotive air bag, if the gas has a d
    5·1 answer
  • 2. The heat energy fequired to change a
    8·1 answer
  • CHEMISTRY HELP!
    14·1 answer
  • for each compound write a complete reaction equation showing the removal of the atoms that become the water molecule
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!