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3 years ago

7

HELP!!!! Please choose the correct label for this diagram A. Fossil Correlation B. Uniformitarianism C. Faunal Succession D. Fos

sil Communication System - FCS

2 answers:

Elenna [48]3 years ago

6 0

Answer:

=B

Explanation:

I think the B is correct answer

Anna35 [415]3 years ago

5 0

Answer:

Uniformitarianism

Explanation:

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Consider the reaction: 2BrF3(g) --> Br2(g) + 3F2(g)

riadik2000 [5.3K]

Answer : The entropy change of reaction for 1.62 moles of $BrF_3$ reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

$2BrF_3(g)\rightarrow Br_2(g)+3F_2(g)$

The expression used for entropy change of reaction $(\Delta S^o)$ is:

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]$

where,

$\Delta S^o$ = entropy change of reaction = ?

n = number of moles

$\Delta S_f^0$ = standard entropy of formation

$\Delta S_f^0_{(Br_2)}$ = 245.463 J/mol.K

$\Delta S_f^0_{(F_2)}$ = 202.78 J/mol.K

$\Delta S_f^0_{(BrF_3)}$ = 292.53 J/mol.K

Now put all the given values in this expression, we get:

$\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]$

$\Delta S^o=268.74J/K$

Now we have to calculate the entropy change of reaction for 1.62 moles of $BrF_3$ reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of $BrF_3$ has entropy change = 268.74 J/K

So, 1.62 moles of $BrF_3$ has entropy change = $\frac{1.62}{2}\times 268.74=217.68J/K$

Therefore, the entropy change of reaction for 1.62 moles of $BrF_3$ reacts at standard condition is 217.68 J/K

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4 years ago

How are particles in a solid arranged and how do they move

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4 years ago

Calculate the quantity of electricity obtained from 2 moles of electrons

Vinil7 [7]

The quantity of electricity : 2 Faraday = 193000 Coulomb

<h3>Further explanation</h3>

Given

2 moles of electrons

Required

The quantity of electricity

Solution

According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts

1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.

The conversion / relationship can be stated as follows:

1 Faraday = 1 mole of electrons = 96500 Coulombs

1 faraday = coulomb / 96500

Can be formulated

Coulomb = Q = I. t so:

$\large {\boxed {\bold {1 \: Faraday \: = \: \dfrac {i \: x \: t} {96500}}}}$

so for 2 moles electrons :

= 2 x 96500 C

= 193000 C

= 2 Faraday

6 0

3 years ago