Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
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Answer:
Li₂CO₃ ⇒ Li₂O + CO₂ is a decomposition reaction.
Explanation:
In a decomposition reaction, a single substance decomposes, producing two or more different substances. In other words, in this type of reaction two or more substances are formed from a compound. The atoms that form a compound separate to give the products according to the formula:
AB → A + B
It can occur spontaneously, or be aided by a catalyst, heat, or electrolysis.
In this case:
Li₂CO₃ ⇒ Li₂O + CO₂ It is a type of chemical reaction in which a single compound decomposes into two or more compounds. So it is a decomposition reaction.
Answer:
copper
Explanation:
metallic bonds occur among the metal atoms where iconic bonds join metal and nonmetals metallic bonding joins a bolt of metal atoms a sheet of aluminum foil and a copper wire are both place where you can see metallic bonding in action the Sea of electrons that is free to flow about the crystal of positive metal ions
