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olasank [31]
3 years ago
5

21.82 L of 4.65 M HCl is added to 9.31 L of 8.55 M NaOH. What is the concentration of HCl in the resulting solution? **hint: mak

e ICE table
A)1.90 M

B)0.952 M

C)10.3 M

D)0.702 M

E)0.644 M
Chemistry
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

D

Explanation:

First you multiply 4.65 with 21.82 to get the mols of hcl, which is 101.463. Then you make an ice table. The ice table should look like this:

HCl       +  NaOH     =  12NaCl + H2O

101.463   6.022e23   1.989e30

As the ice table above shows, you will have 1.989e30 mols of nacl after the reaction. With that information, you can then divide it by 2.833333333333333e30 to get 0.702 M.

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What is the percent of Cr in Cr2O3
IgorLugansk [536]
The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
           Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
     2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
          Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
                   = \frac{103.98}{151.98} × 100
                   
                   = 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
5 0
3 years ago
Read 2 more answers
What is the molarity of a 4.447 L solution
igomit [66]

Answer:52M

Explanation:

use S= 1000w/ MV

Here, s= molarity

w= the amount of NaCl

M= the atomic mass of NaCl

V= the volume of solution

4 0
3 years ago
The nerve that relays visual infor to several part of your brain is the _____ nerve.
Lemur [1.5K]

Answer:

Optic nerve

Explanation:

8 0
3 years ago
a student prepares a dilute solution of sodium hydroxidem, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.
Serjik [45]

Answer:

M = 0.3077 M

Explanation:

As I said in the comments, you are missing the required volume of the base to react with the KHP. I found this on another site, and the volume it used was 21.84 mL.

Now, KHP is a compound often used to standarize NaOH or KOH solutions. This is because it contains a mole ratio of 1:1 with the base, so it's pretty easy to use and standarize any base.

Now, as we are using an acid base titration, the general expression to use when a acid base titration reach the equivalence point would be:

n₁ = n₂   (1)

This, of course, if the mole ratio is 1:1. In the case of KHP and NaOH it is.

Now, we also know that moles can be expressed like this:

n = M * V   (2)

And according to this, we are given the volume of base and the required mass of KHP. So, if we want to know the concentration of the base, we need to get the moles of the KHP, because in the equivalence point, these moles are the same moles of base.

The reported molar mass of KHP is 204.22 g/mol, so the moles are:

n = 1.372 / 204.22 = 6.72x10⁻³ moles

Now, we will use expression (2) to get the concentration of the diluted base:

n = M * V

M = n / V

M = 6.72x10⁻³ / 0.02184

M NaOH = 0.3077 M

This is the concentration of the dilute solution of NaOH

3 0
3 years ago
What is the percent yield of LiCl if I produced 30.85g LiCl and my theoretical yield was calculated to be 35.40g LiCl?
marissa [1.9K]

Answer:

87.15%

Explanation:

To find percent yield, we can use this simple equation

\frac{Actual}{Theoretical} *100

Where "Actual" is the amount in grams actually collected from the reaction, and "Theoretical" is, well, the theoretical amount that should have been produced.

They give us these values, so to find the percent yield, just plug the numbers in.

\frac{30.85}{35.40} *100\\\\ =87.15

So, the percent yield is 87.15%

An easy trick to remember how to do this is just to divide the smaller number by the bigger number and move the decimal back two places. If you have a percent yield greater than 100%, something is wrong in the reaction.

7 0
3 years ago
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