Answer:
691.6 torr
Explanation:
Given data:
Initial temperature = 273 K
Initial pressure = 1 atm
Final temperature = -25 °C (-25 + 273 = 248 k)
Final pressure = ?
Solution:
P₁/T₁ = P₂/T₂
P₁ = Initial pressure
T₁ = Initial temperature
P₂ = Final pressure
T₂ = Final temperature
Now we will put the values in formula.
P₁/T₁ = P₂/T₂
P₂ = P₁T₂/T₁
P₂ = 1 atm × 248 K / 273 k
P₂ =248 atm. K / 273 K
P₂ = 0.91 atm
In torr:
0.91 × 760 = 691.6 torr
Answer:
I > III > II
Explanation:
The osmotic pressure (π) is a colligative property that can be calculated using the following expression.
π = M × R × T
where,
M is the molarity of the solution
R is the ideal gas constant
T is the absolute temperature
As we can see, there is a direct proportionality between the molarity of the solution and its osmotic pressure. As a consequence, the correct order for osmotic pressures is:
I > III > II
A) radius: 1.4cm
diameter: 2.8cm
b) radius: 2.1cm
diameter: 4.2cm
Answer:
I think it's 78. I might be wrong I'm not sure.
Explanation:
