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ELEN [110]
2 years ago
13

can anyone help with this mole to mole/mole to grams question? any help would be greatly appreciated! Thanks!

Chemistry
1 answer:
goldenfox [79]2 years ago
8 0

Answer:

Explanation:

a) 3.00 mol Cu x 2 mol Ag/ 1 mol Cu = 6 mol Ag

b) 3.00 mol Cu x 2 mol Ag/1 mol Cu x 107.87g Ag/ 1 mol Ag = 647.22g Ag

c) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu = 3 mol Cu(NO3)2

d) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu x 187.54g/ 1 mol Cu(NO3)2 =562.644g Cu(NO3)2

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Which product of the ultraviolet decomposition of cfcs acts as the catalyst for ozone decomposition?
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Which of the following gives the definition of ion-dipole attraction? Select the correct answer below: O a. lon-dipole attractio
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Answer:

D

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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution when ex
mojhsa [17]

Answer:

a. 1.78x10⁻³ = Ka

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Explanation:

a. The neutralization of a weak acid, HA, with a base can help to find Ka of the acid.

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HA ⇄ H⁺ + A⁻

And Ka is defined as:

Ka = [H⁺] [A⁻] / [HA]

The HA reacts with the base, XOH, thus:

HA + XOH → H₂O + A⁻ + X⁺

As you require 26.0mL of the base to consume all HA, if you add 13mL, the moles of HA will be the half of the initial moles and, the other half, will be A⁻

That means:

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It is possible to obtain pKa from H-H equation (Equation used to find pH of a buffer), thus:

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Replacing:

2.75 = pKa + log₁₀ [A⁻] / [HA]

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2.75 = pKa + log₁₀ 1

<h3>2.75 = pKa</h3>

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2.75 = -log Ka

10^-2.75 = Ka

<h3>1.78x10⁻³ = Ka</h3>

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Answer:

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