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2 years ago

can anyone help with this mole to mole/mole to grams question? any help would be greatly appreciated! Thanks!

Chemistry

1 answer:

goldenfox [79]2 years ago

8 0

Answer:

Explanation:

a) 3.00 mol Cu x 2 mol Ag/ 1 mol Cu = 6 mol Ag

b) 3.00 mol Cu x 2 mol Ag/1 mol Cu x 107.87g Ag/ 1 mol Ag = 647.22g Ag

c) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu = 3 mol Cu(NO3)2

d) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu x 187.54g/ 1 mol Cu(NO3)2 =562.644g Cu(NO3)2

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How many electrons are represented by a dash (-) in a lewis dot structure compound

wlad13 [49]

Answer:

nstead of using two dots to indicate the two electrons that comprise the covalent bond, a line is substituted for the two dots that represent the two electrons. Below is shown the Lewis structure for water. Two hydrogens (H) are separately covalently bonded to the central oxygen (O) atom.

Explanation:

4 0

3 years ago

Read 2 more answers

How can you determine the number of protons and neutrons in an isotope when given the symbol and mass number?

alekssr [168]

When given the symbol, you can look on the periodic table of elements to find what the atomic number is, which is the number in the corner next to the symbol. The number of protons in the element is the atomic number. The number of neutrons is the mass number minus the number of protons.
Hope it helps:)

7 0

2 years ago

A hydrogen atom is in its fifth excited state. The atom emits a wavelength photon. Determine the maximum possible orbital angula

forsale [732]

Answer:

(√ 20) hbar.

Explanation:

The first thing to do is to calculate the second principal quantum number, n from the formula for Calculating energy,E and this is done as given below;

Energy, E = 13.6 (1 / n^2 - 1/6).

(Where energy,E = 1240/ 7474).

Hence, when we solve the above equation for n, the principal quantum number = 5.

We know that the azimuthal quantum Number, l = (n- 1); 5 - 1 = 4.

Therefore, the maximum possible magnitude of the orbital angular momentum of the atom after emission = (√ 4 × 5) hbar.

the maximum possible magnitude of the orbital angular momentum of the atom after emission = (√ 20) hbar.

Note that hbar = 1.0545718 × 10-34 m2 kg / s.

8 0

2 years ago

Which equation represents a conservation of atoms? Group of answer choices LaTeX: 4Fe\:+3O_2\:\longrightarrow\:2Fe_2O_3 4 F e +

slamgirl [31]

Answer : The equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Explanation :

Law of conservation of matter : It states that matter can neither be created nor be destroyed but it can only be transformed from one form to another form.

The balanced chemical reaction always follow the law of conservation of matter.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

(1) The given chemical reaction is,

$4Fe+3O_2\rightarrow 2Fe_2O_3$

This reaction is a balanced chemical reaction in which number of atoms of iron and oxygen are equal on the both side of the reaction. So, this reaction obey the law of conservation of matter.

(2) The given chemical reaction is,

$2Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of iron and oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

(3) The given chemical reaction is,

$4Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

Hence, the equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

3 0

2 years ago

An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

Answer: The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$