What me with this work sheet plllzz

If you add a chunk of zinc to a beaker of acid and zinc shavings to another beaker of acid, the sample with the zinc shavings wi

Svet_ta [14]

Answer:

The answer to your question is: letter C

Explanation:

The only difference between the samples of Zinc is their presentation, one is a chunk of zinc and the other one is shavings.

1) Catalyst This option is incorrect because the description

do not mention anything about catalyst.

2) Nature of the reaction The nature of the reaction is the same.

3) Surface area This is the right answer because in the chunk

there is less surface area than in the shavings.

4) Temperature It is not mention anything about temperature in

the description.

8 0

4 years ago

37)

Natali [406]

Answer:

dont know

Explanation:

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7 0

3 years ago

After creating a definition for what it means to be sexually abstinent, list reasons why being abstinent is important for you an

Sever21 [200]

Sexually abstinent: refraining from some or all sexual activities
school (higher education)
health (stds)
pregnancy (not ready for children)

5 0

3 years ago

The element silver (Ag) has two naturally occurring isotopes: 109Ag and 107Ag with a mass of 106.905 amu. Silver consists of 51.

algol [13]

Answer:

108.76 amu is the mass of 109Ag

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 109Ag:

% = 51.82 %

Mass = x amu

For second isotope, 107Ag:

% = 100 - x = 100 - 51.82 % = 48.18 %

Mass = 106.905 amu

Given, Average Mass = 107.868 amu

Thus,

$107.868=\frac{51.82}{100}\times {x}+\frac{48.18}{100}\times {106.905}$

Solving for x, we get that:

x = 108.76 amu

108.76 amu is the mass of 109Ag

6 0

3 years ago

a regular solid has a length of 28cm. , a width of 16cm. and a total surface area of 1424cm squared. What is the total surface a

Brrunno [24]

Answer:

A = 356 cm²

Explanation:

In this case, you need to use the formula to calculate the area of regular solid.

This is the following expression:

S = 2LH + 2LW + 2WH

Where:

L: length

W: Width

H: Height

But we do not know the height of the solid. We should calculate it with the given data first:

1424 = 2*28*H + 2*28*16 + 2*16*H

1424 = 56H + 896 + 32H

1424 - 896 = 88H

H = 528/88

H = 6 cm

Now that we know the height we can calculate the area of the other solid. In the other solid the length has been reduced to half, so I will assume that the Width and height is also reduced to half.

L2 = 14 cm

W2 = 8 cm

H2 = 3 cm

Replacing we have:

S = (2*14*3) + (2*14*8) + (2*8*3)

S = 356 cm²

And this should be the total surface area, assuming the width and height is reduced to half too.

If you don't assume it's reduced to half, then use the original values of Width and Height. Doing so, the Surface would be:

S = (2*14*6) + (2*14*16) + (2*6*16)

S = 808 cm²

5 0

3 years ago