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netineya [11]
3 years ago
7

When a pot of water sits on a hot stove, the metal pot is heated, and then transfers its heat to the water. A student claims tha

t conduction is the only type of heat transfer occurring. Which statement explains why the student's idea is incorrect?
a. Conduction cannot occur between two different phases of matter.
b. The water transfers heat within the pot by convection.
c. Water cannot be heated by electromagnetic radiation.
d. Metal is a poor conductor of heat.
Chemistry
2 answers:
finlep [7]3 years ago
3 0

When a pot of water sits on a hot stove, the metal pot is heated, and then transfers its heat to the water. A student claims that conduction is the only type of heat transfer occurring. The statement that explains why the student’s idea is incorrect Conduction cannot occur between two different phases of matter. The answer is letter A.

MissTica3 years ago
3 0

Answer: Option (A) is the correct answer.

Explanation:

When we heat a fluid then the cooler material which is more denser in nature will sink at the bottom whereas the hot material which is less denser in nature will rise at the top. This flow of material induces currents and the process is known as convection.

For example, when a metal pot of water is heated then heat will be transferred from pot to the water represents convection process.

Whereas when two objects are touching each other and both of them have different temperature then heat will flow from warmer object to cooler object. This process is known as conduction.

Thus, we can conclude that the statement conduction cannot occur between two different phases of matter explains why the student's idea is incorrect.

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Which equation correctly relates the heat of reaction to the standard heats of formation?
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Answer:

D

Explanation:

∆H° = ∆Hf ° (products) – ∆Hf ° (reactants)

4 0
3 years ago
What is the fourth largest element on the periodic table?
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I think it's the Pentium up
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A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
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800 joules because it's twice the amount
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3 years ago
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If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
Veseljchak [2.6K]

Answer:-

29.07 gram of Cu(NO3)2 will be formed.

4.756 grams of AgNO3 will be left over when the reaction is complete.

Explanation:-

Atomic weight of Cu = 63.546 g mol -1

Molecular weight of AgNO3 = 107.87 x 1 + 14 x 1 + 16 x 3

= 169.87 g mol-1

Number of moles of Copper = 9.85 gram / (63.546 g mol-1)

= 0.155 mol

Number of moles of AgNO3 = 31 gram / ( 169.87 g mol-1)

= 0.183 mol

The balanced chemical equation for this reaction is

Cu + AgNO3 --> Cu(NO3)2 + Ag

According to the equation,

1 mole of Cu reacts with 1 mole of AgNO3.

∴0.155 mol of Cu react with 0.155 mol of AgNO3.

Number of moles of AgNO3 left over = 0.183-0.155=0.028 mol

Number of grams of AgNO3 left over = 0.028 mol x 169.87 grams mol-1

= 4.756 gram

Molecular weight of Cu(NO3)2 = 63.546 x 1 + (14 x 1 +16 x 3 ) x 2

=187.546 gram

Now from the balanced chemical equation,

1 Cu gives 1 Cu(NO3)2

∴ 63.546 g of Cu gives 187.546 gram of Cu(NO3)2

9.85 grams pf Cu gives 187.546 x 9.85 / 64.546 gram of Cu(NO3)2

= 29.07 gram of Cu(NO3)2

4 0
3 years ago
A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H₂O
ollegr [7]

Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.381g

Mass of H_2O=0.692g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, \frac{2}{18}\times 0.692=0.0769g of hydrogen will be contained.

Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

This means that there is no other element present in the compound.

3 0
3 years ago
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