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Nimfa-mama [501]
3 years ago
13

An iron nail rusts when exposed to oxygen. According to the following reaction, how many moles of iron(III) oxide will be formed

upon the complete reaction of 32.2 grams of iron with excess oxygen gas ? iron(s) + oxygen(g) iron(III) oxide(s) moles iron(III) oxide
Chemistry
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

0.453 moles

Explanation:

The balanced equation for the reaction is:

2Fe(s) + 3O2(g)  ==>  2Fe2O3

From the equation,  mass of O2 involved = 16 x 2 x 3 = 96g

                                 mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2

                                                                            = 100g

                Therefore 96g of O2 produced 100g of Fe2O3

                                  32.2g of O2 Will produce   100x32.2/96

                                                   = 33.54g of Fe2O3

Converting it to mole using   number of mole = mass/molar mass

but molar mass of Fe2O3 = 26 + (16 X 3)

                                           = 74g/mole

Therefore number of mole of 33.54g of Fe2O3 = 33.54/74

                                                                           = 0.453 moles

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How many grams of a 5.5% solution can be prepared from 25 kg KCl
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Answer:

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Here's a point to be kept in mind :

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The concentration of a solution is most of the time expressed as the number of moles of solute present in 1 Liter of the solution (also called molarity )

(There are also other ways to express concentration. Please follow this link. )

EXAMPLE:

(a) If 25 moles of NaCl are present in 100 L of a solution wherein H2O is the solvent, then the concentration of the solution is

25

100

=

0.25

mol⋅L

−

1

.

(b) What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution?

Solution

Calculate the number of moles of solute present.

Moles of NaOH = 15.0 g NaOH ×

1

mol NaOH

40.00

g NaOH

= 0.375 mol NaOH

Calculate the number of litres of solution present.

Volume = 225 mL ×

1

L

1000

mL

= 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

Molarity =

0.375

mol

0.225

L

= 1.67 mol/L

Explanation:

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