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tekilochka [14]
3 years ago
6

A 12-foot high ladder reaches a tree limb when it leans at a 36 degree angle with the ground. Approximately how far away is the

base of the ladder from the tree trunk base?

Mathematics
1 answer:
Allisa [31]3 years ago
4 0
Look at the picture.

\cos 36^\circ = \frac{x}{12} \\
0.809 \approx \frac{x}{12} \\
0.809 \times 12 \approx x \\
x \approx 9.708

The base of the ladder is approximately 9.708 feet from the tree trunk base.

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Mila reads at a rate of 3 paragraphs per minute.
Alexxx [7]

Answer:

y= 3x

Step-by-step explanation:

This is honestly your basic times tables if we are being honest. We know that she read 3 paragraphs per minute. We also know that in 4 minutes, she read 12 paragraphs. 4 times 3 = 12. So the answer is y=3x.

7 0
3 years ago
Help ASAP! 20 pts. Will give brainliest for right answer
Anestetic [448]
The answer is B (3,-2)

6 0
3 years ago
Read 2 more answers
A baseball team has home games on Thursday and Saturday The two games together earn ​$4061.50 for the team. Thursday​'s game gen
marta [7]
The team made 2,061.50 at the first game and 2,000.00 at the second game. Because 2,000.00 would be 61.50 less than the amount made at the first game. You can check it by adding 2,061.50 + 2,000.00 which equals $4,061.50.
7 0
3 years ago
Express y in terms of x
saw5 [17]

Answer:

see explanation

Step-by-step explanation:

(a)

Given y is inversely proportional to x² then the equation relating them is

y = \frac{k\\}{x^2} ← k is the constant of variation

To find k use any ordered pair from the table.

Using (1, 4 ) , then

4 = \frac{k}{1^2} = \frac{k}{1} ( multiply both sides by 1

4 = k

y = \frac{4}{x^2} ← equation of variation

(b)

When y = 25 , then

25 = \frac{4}{x^2} ( multiply both sides by x² )

25x² = 4 ( divide both sides by 25 )

x² = \frac{4}{25} ( take the square root of both sides )

x = ± \sqrt{\frac{4}{25} } = ± \frac{2}{5}

Since x > 0 then x = \frac{2}{5}

5 0
3 years ago
The quadratic equation y = –6x2 + 100x – 180 models the store’s daily profit, y, for selling soccer balls at x dollars.
Norma-Jean [14]

Answer:

The point of intersections are (1.838, -16.49) and (8.16, 236.49).

The point (1.838, -16.49) represent that the loss for selling soccer balls equals loss for selling footballs when they are sold at a price of 1.84 dollars and the loss is $16.49.

The point (8.16, 236.49) represent that the profit for selling soccer balls equals profit for selling footballs when they are sold at a price of 8.16 dollars and the profit is $236.49.

Step-by-step explanation:

Given:

The daily profit expression for selling soccer balls is given as:

y=-6x^2+100x-180

The daily profit expression for selling footballs is given as:

y=-4x^2+80x-150

The graph is drawn as shown below. From the graph, the points of intersection of the two functions are (1.838, -16.49) and (8.16, 236.49).

Therefore, for selling price equal to 1.84 dollars, there is negative profit which means they will have loss. The daily loss for selling both soccer balls and footballs would be same and equal to $16.49.

For selling price equal to 8.16 dollars, there is positive profit. The daily profit for selling both soccer balls and footballs would be same and equal to $236.49.

7 0
3 years ago
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