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stepladder [879]
2 years ago
9

Suppose that it is reported in the news that 12% of the people living and working in Kokomo feel that their commute is too long.

What is the travel time to work that separates the top 12% of people with the longest travel times and the lower 88%
Mathematics
1 answer:
Dominik [7]2 years ago
4 0

Answer:

22.3 minutes

Step-by-step explanation:

The computation of the travel time is as follows:

Given that

\mu = 17

And, the standard deviation is 4.5

P(X≤C) = 0.88

P( x - \mu) ÷ \sigma ≤  (C - \mu)  ÷ \sigma  = 0.88

(C - \mu)  ÷ \sigma  = 1.175

c = \mu +  1.175 × \sigma

= 17 + 1.175 × 4.5

= 22.3 minutes

Hence, the travel time is 22.3 minutes

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Answer:

x= -6

Step-by-step explanation:

y=4x-6

y=5x, so where ever you see y, put 5x there.

hence, 5x=4x-6

5x-4x=-6

x= -6

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3 years ago
15 POINTS. What is the area of the circle segment/shaded area? Picture included please help. Please answer in a way that will fi
PilotLPTM [1.2K]
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Find measure of angle b
nordsb [41]

I cant see the problem

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3 years ago
Amber, Bernie, and Carlos are working on a problem together. Their goal is to correctly apply the difference of cubes formula to
NeX [460]

Answer: Carlos is correct

Step-by-step explanation:

2x^5-250x^2

The first step is to factorize out 2x^2

2x^2(x^3-125)

This can be rewritten as

2x^2(x^3-5^3),

Recall, difference if cube (a^3-b^3)

= (a-b)(a^2 +ab + b^2)

from our equation,

a= x

b = 5.

So the difference of cubes will be

2x^2[(x-5) (x^2 + 5x + 5^2)]

=2x^2[(x-5) (x^2 + 5x + 25)]

Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.

Amber is incorrect because 125 is equal to b3, not b.

Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.

6 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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