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4 years ago

The square below has an area of x^2+10x+25 square meters. What expression represents the length of one side of the square?

Mathematics

1 answer:

Andre45 [30]4 years ago

8 0

(x+5) represents each side of a square. Since all sides of a square are equal, we know that all sides are (x+5).

Base x height = (x+5)(x+5)

Which is x^2+10x+25!

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What is the solution of StartRoot x + 12 EndRoot = x?

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Note: Figure is not drawn to scale.

Shalnov [3]

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6 0

3 years ago

Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou

Andru [333]

Answer:

Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

Finding the sides of the quadrilateral using the Distance formula:

A(-3,0), B(2,4), C(3,1) and D(-4,-3)

$AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\$

$=6.40$

BC=

$\sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}$

$=3.16$

$CD=\sqrt{(-4-3)^2+(-3-1)^2} \\\\=\sqrt{(-7)^2+(-4)^2} \\\\=\sqrt{49+16}\\\\=\sqrt{65}\\\\ =8.06$

$AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16$

Perimeter of the quadrilateral= AB+BC+CD+AD

=6.40+3.16+8.06+3.16

=20.78

6 0

3 years ago