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4 years ago

What do typing on a computer, lifting a box, and putting on a sweater have in common?

Physics

1 answer:

Ostrovityanka [42]4 years ago

8 0

For each one . . .

-- some part of your body has to move

-- you convert some chemical energy into kinetic energy when you make muscles move

-- a human being can do it but an animal can't.

Wellll, maybe a monkey can lift a box. 2 out of 3 ain't too bad.

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A third class lever has a mechanical advantage of <1. What is an example of a third class lever and why use it?

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Answer: Choice B: baseball bat; increases velocity

Explanation:

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A very long, solid insulating cylinder has radius R; bored along its entire length is a cylindrical hole with radius a. The axis

lawyer [7]

Answer:

The value of the electric field is $E_{net} = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

Explanation:

We know that the electric field inside a solid cylinder at a distance $\textbf{r}$ from the centre is given by

$E = \dfrac{\rho \textbf{r}}{2 \epsilon_{0}}$

Let's consider the cross-section of the cylinder as shown in the figure. Let `O' be the centre of the long solid insulating cylinder having radius 'R'. Also consider that $O'$ be the cetre of the hole of radius 'a' situated at a distance 'b' from 'O'. Given, the volume charge density of the material is 'r'. So, the volume charge density inside the hole will be '-r'. Let's consider 'P' be any arbitrary point inside the hole situated at a distance 's' from $O'$ .

So, the electric field ' $E_{O}$ ' due to the long cylinder at point 'P' is given by

$E_{O} = \dfrac{r \textbf{c}}{2 \epsilon_{0}}$

and the electric field ' $E_{O'}$ 'due to the hole at point 'P' is given by

$E_{O'} = \dfrac{\rho \textbf{s}}{2 \epsilon_{0}}$

So the net electric field ( $E_{net}$ ) inside the hole is given by

$E_{net} = E_{O} - E_{O'} = \dfrac{r}{2\epsilon_{0}}(\textbf{c - s}) = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

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4 years ago

Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field

Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. True

Electric field lines are continuous; they do not have a beginning or an ending. False

Electric field lines can never intersect. True

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending. False

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. True

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

This statement correspond to the definition of the field line.

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Answer:

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