You can increase the gravitational potential between a car and the road by

Both atypical and traditional antipsychotics _____ levels of _____.

LiRa [457]

Answer:

Both atypical and traditional antipsychotics blocks levels of serotonin.

Explanation:

These drugs are capable of reducing or turning off positive psychotic symptoms such as hallucinations, delusions, and language and behavior disorder.

In addition to also acting as mood stabilizers, they have an impact on mania, depression, and produce low anxiety.

These anti-psychotics work on the 5-HT2A receptor, it belongs to the family of serotonin receptors and it is a G protein-coupled receptor. 5-HT is short for 5-hydroxy-tryptamine, the chemical name for serotonin.

This receptor became notorious for its importance as a target for drugs like LSD. Later it became important again due to the action of many antipsychotic drugs, especially atypical ones.

5 0

3 years ago

What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 49 k

Molodets [167]

Answer:

$\dfrac{I_1}{I_2}=12.25$

Explanation:

$r_1$ = 14 km

$r_2$ = 49 km

Intensity of a wave is inversely proportional to distance

$I\propto \dfrac{1}{r^2}$

So,

$\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{49^2}{14^2}\\\Rightarrow \dfrac{I_1}{I_2}=12.25$

The ratio of the intensities is $\dfrac{I_1}{I_2}=12.25$

6 0

3 years ago

What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
m is mass
a is acceleration

In our case,

F = ?
m = 2500 kg
a = 20m/s

$\tt \: F_{net} = 2500 \times 20 \\ \tt= 50000$

Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~

3 0

2 years ago

Read 2 more answers

Diagram of an atom with labels

lina2011 [118]

See this. I hope you find your answer

6 0

3 years ago

A baseball pitcher throws a ball horizontally at a speed of 34.0 m/s. A catcher is 18.6 m away from the pitcher. Find the magnit

Sidana [21]

To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.

The trajectory equation from the motion kinematic equations is given by

$y = \frac{1}{2} at^2+v_0t+y_0$

Where,

a = acceleration

t = time

$v_0$ = Initial velocity

$y_0$ = initial position

In addition to this we know that speed, speed is the change of position in relation to time. So

$v = \frac{x}{t}$

x = Displacement

t = time

With the data we have we can find the time as well

$v = \frac{x}{t}$

$t = \frac{x}{v}$

$t = \frac{18.6}{34}$

$t = 0.547s$

With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,

$y = \frac{1}{2} at^2+v_0t+y_0$

$y = \frac{1}{2} gt^2+0+0$

$y = \frac{1}{2} gt^2$

$y = \frac{1}{2} 9.8*0.547^2$

$y = 1.46m$

Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.

6 0

3 years ago