Question

A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum of the box? (unit = kg*m/s)

Answer 1

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

Answer 2

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s