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Paraphin [41]
3 years ago
7

A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum

of the box? (unit = kg*m/s)
Physics
2 answers:
bixtya [17]3 years ago
4 0

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

lana [24]3 years ago
3 0

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s

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Answer:

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Explanation:

Given the data in the question;

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VHned = IB

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3 years ago
An advantage of parallel circuits is that they A) stop transmitting all current if even one resistor breaks. B) form a single pa
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4 0
3 years ago
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maw [93]
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hope this helps
4 0
3 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

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3 years ago
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