a tree truck
is the answer i hope this helps you xD
Answer: The first answer for the first problem, and the 2nd answer for the second problem
Explanation: For the first one, if it is absolute zero, the molecules would not move at all.
For the second one, the temperature of the sample will increase due to the movement.
Answer:
c)
Explanation:
As we know that resultant force is the net force that is acting on the system
As per Newton's II law we know that net force is product of mass and acceleration
so we will have

here we know
m = 80 kg
for circular motion acceleration is given as


now we have



Answer:
The correct answer would be 200m
Explanation:
20x10=200
the previous answer is incorect from the other user.
- initial velocity=u=24m/s
- Acceleration=a=4m/s^2
- Distance=s=96m
- Final velocity=v
Using 3rd equation of kinematics






