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Neko [114]
2 years ago
11

HELP PLS !!! Calculate the total current drawn from the 9-volt battery

Physics
1 answer:
cricket20 [7]2 years ago
6 0

Answer:

0.82A

Explanation:

first we resolve the resistors in parallel

i.e 1/R=1/R1+1/R2

=1/R=1/6+1/3

1/R=1/2

R=2/1=2ohms

now we resolve all resistors in series

R=R1+R2+R3

R=6+3+2(the two parallel resistors we resolved are now in series with the others)

R=11ohms

From ohm's law V=IR

I=V/R=9/11= 0.82A.

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(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)

Answer:

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Explanation:

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K_{i}+U_{i}=K_{f}+U_{f} (1)

With K_{i} the initial kinetic energy, U_{i} the initial potential energy, K_{f} the final kinetic energy and U_{f} the final potential energy. Note that initialy the masses are at rest so K_{i} = 0, when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so K_{f} =0. So, equation (1) becomes:

U_{i}=U_{f} (2)

At initial moment all the potential energy is gravitational because the spring is not stretched so U_{i}=U_{gi} and at final moment we have potential gravitational energy and potential elastic energy so U_{f}=U_{gf}+U_{ef}, using this on (2)

U_{gi}=U_{gf}+U_{ef} (3)

Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), U_{gi}=0 and we have by (3) :

0= U_{gf}+U_{ef} (4)

Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:

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dividing both sides by d

0=-m1g+m2g+\frac{kd}{2}

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What objects do balanced forces act on?
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Suppose you pour 0.250 kg of 20.0°C water into a 0.600 kg aluminum pan off the stove with a temperature of 173°C. Assume that th
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Answer:

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Explanation:

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<u>Using the equation of heat:</u>

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m_p.c_a.(T_{ip}-T_f)=m_v.L+(m_w-m_v).c_w.(T_f-T_{iw})

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