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VARVARA [1.3K]
3 years ago
11

What forces act on human body in equilibrium.​​

Physics
1 answer:
shusha [124]3 years ago
8 0

Explanation:

ear drum

muscular force

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Question 1<br> 2.5 cm=<br> mm
Nookie1986 [14]
There’s 10mm in a cm: 22mm
8 0
3 years ago
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A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult
Dvinal [7]

Answer:

Explanation:

Given

time taken t=2\ s

Speed acquired in 2 sec v=42\ m/s

Here initial velocity is zero u=0

acceleration is the rate of change of velocity in a given time

a=\frac{v-u}{t}

a=\frac{42-0}{2}=21\ m/s^2

Distance travel in this time

s=ut+0.5at^2

where  

s=displacement

u=initial velocity

a=acceleration

t=time

s=0+\0.5\times 21\times (2)^2

s=42\ m

so Jet Plane travels a distance of 42 m in 2 s                                

5 0
3 years ago
The universal law of gravitation states that the force of attraction between two objects depends on which quantities?
STALIN [3.7K]

Answer: The answer is the masses of the objects and the distance between them

Explanation: Gravity is affected by mass and distance between two objects becuase if and object is too far the force of gravity will not be strong. The larger the object, the stronger the force of gravity will be.

3 0
3 years ago
Force → F = ( − 8.0 N ) ˆ i + ( 6.0 N ) ˆ j acts on a particle with position vector → r = ( 3.0 m ) ˆ i + ( 4.0 m ) ˆ j . What a
andrey2020 [161]

Explanation:

It is given that,

Force, F=(-8\ N)i+(6\ N)j

Position vector, r=(3i+4j)\ m

(a) The torque on the particle about the origin is given by :

\tau=F\times r\\\\\tau=(-8i+6j)\times (3i+4j)\\\\\tau=(-50k)\ N-m

(b) To find the angle between r and F use dot product formula as :

F{\cdot} r=|F||r|\ \cos\theta\\\\\cos\theta=\dfrac{F{\cdot} r}{|F| |r|}\\\\\cos\theta=\dfrac{(-8i+6j){\cdot} (3i+4j)}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=\dfrac{-24+24}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=0\\\\\theta=90^{\circ}

Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
A long wave with a period of about 15 minutes will travel across the oceans at a speed of approximately _______.
Temka [501]

The speed of the wave  is mathematically given as

v=2266.66m/s

A long wave with a period of about 15 minutes will travel across the oceans at a speed of approximately v=2266.66m/s

<h3>Speed of the wave</h3>

Question Parameters:

A long wave with a period of about 15 minutes

Generally the equation for the Wave velocity  is mathematically given as

v=\lambda * frequency

Where

f=1/t

Therefore

v=\lambda * frequency

v=\lambda * 1/t

Therefore, with wavelenght of the ocean as 34km

v=34*1000*1/15

v=2266.66m/s

For more information on Speed

brainly.com/question/4931057

7 0
2 years ago
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