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Tems11 [23]
3 years ago
8

What year did i start high school if i graduate in 2017?

Mathematics
1 answer:
Karolina [17]3 years ago
5 0
Obviously, 2013. 2013-2014 (1 year) 2014-2015 (2 years) etc etc
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If you flip a pair of coins 48 times, how many times are you most likely to get 2 heads.
pentagon [3]
But actually its based on your luck
3 0
3 years ago
In a collision, a 5 kg mass moving at 2m/s transfers all of its momentum to a 1 kg mass. What is the velocity of the 1kg mass af
statuscvo [17]
Answer:
velocity = 10 m/sec in the same direction as the first body did

Explanation:
The momentum of the body can be calculated as follows:
momentum = mass * velocity

For the first body, we have:
mass = 5 kg
velocity = 2 m/sec
momentum = mass * velocity
momentum = 5 * 2 = 10 kg.m/sec

We know that this momentum is transferred completely to the second body

For the second bode, we have:
momentum = 10 Kg.m/sec
mass = 1 kg
momentum = mass * velocity
10 = 1 * velocity 
velocity = 10/1
velocity = 10 m/sec

Finally, we should get the direction of the motion:
Both the velocity of the first and second bodies have positive values. Therefore, the second body is moving in the same direction as the first body did.

Hope this helps :)
6 0
3 years ago
Read 2 more answers
Find the limit, if it exists, or type dne if it does not exist.
Phantasy [73]
\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
8 0
3 years ago
What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

=(6+2-3-4)\sqrt{3}

=\sqrt{3}

The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

8 0
3 years ago
Need help ASAP ? <br>3/4×20
In-s [12.5K]

3/4 x 20

3/4 x 20/1

3 x 20 = 60

4 x 1 = 4

60 / 4 = 15

8 0
4 years ago
Read 2 more answers
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