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galina1969 [7]
3 years ago
11

Weight is a force that depends on mass and: *

Physics
2 answers:
Rashid [163]3 years ago
4 0
B. gravity
because the weight depends on the strength gravitational pull from earth
german3 years ago
4 0
B. Gravity bc it depends on the strength of the gravitational pull
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A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the engine? (1 hp = 746 W) A) 50 hp
sergeinik [125]

Answer:

power, P = 90 hp

Explanation:

It is given that,

Mass of the car, m = 1500 kg

Initial velocity of car, u = 0

Final velocity of car, v = 25 m/s

Time taken, t = 7 s

We need to find the average power delivered by the engine. Work done divided by total time taken is called power delivered by the engine. It is given by :

P=\dfrac{W}{t}

According to work- energy theorem, the change in kinetic energy of the energy is equal to work done i.e.

W=\Delta E=\dfrac{1}{2}m(v^2-u^2)

P=\dfrac{\dfrac{1}{2}m(v^2-u^2)}{t}

P=\dfrac{\dfrac{1}{2}\times 1500\ kg\times (25\ m/s)^2}{7\ s}

P = 66964.28 watts

Since, 1 hp = 746 W

So, P = 89.76 hp

or

P = 90 hp

So, the average power delivered by the engine is 90 hp. Hence, the correct option is (E) " 90 hp".                                                                                                  

6 0
4 years ago
Jack and Nas decided to have a race from their houses to the park to know who runs the fastest. Jack whose house is 15 kilometer
Anettt [7]

Answer:

the Jack speed is greater than the Nas speed  

   v₁ = 2.08 m / s >  v2 = 1.85 m / s

Explanation:

For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval

          v = x / t

Jack.

It tells us that it travels x = 15 km in a time of t = 2 h

let's reduce the magnitudes to the SI system

     x = 15 km (1000 m / 1 km) = 15 10³ m

     t = 2 h (3600 s / 1 h) = 7200 s

let's calculate

     v₁ = 15 10³/7200

     v₁ = 2.08 m / s

Nas travels a distance of x = 10 km in a time of t = 1.5 h

      x = 10 km = 10 10³ m

      t = 1.5 h (3600s / 1h) = 5400 s

let's calculate the speed

     v2 = 10 10³/5400

      v2 = 1.85 m / s

From these results we can see that the Jack speed is greater than the Nas speed

4 0
3 years ago
When you speak, your voice is produced by your vibrating vocal chords. These vibrations produce the ________ which carry _______
Len [333]
Produce waves that carry sound
7 0
3 years ago
A 10.-kilogram object, starting from rest, slides down a frictionless incline with a constant acceleration of 2.0 m/sec2 for fou
aniked [119]

Answer:

C) 100N

Explanation:

Formula for calculating the Weight of an object is expressed as;

Weight = mass × acceleration due to gravity

Given

Mass of the object = 10kg

Acceleration due to gravity = 9.81m/s²

Substitute into the formula above

Weight = 10×9.81

Weight = 98.1N

Hence the approximate weight of the object is 100N

5 0
4 years ago
A car moving at 10.0 m/s encounters a depression in the road that has a circular cross-section with a radius of 30.0 m. What is
Dennis_Churaev [7]

Answer:

F = 789 Newton

Explanation:

Given that,

Speed of the car, v = 10 m/s

Radius of circular path, r = 30 m

Mass of the passenger, m = 60 kg

To find :

The normal force exerted by the seat of the car when the it is at the bottom of the depression.

Solution,

Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.

N=mg+\dfrac{mv^2}{r}

N=m(g+\dfrac{v^2}{r})

N=60\times (9.81+\dfrac{(10)^2}{30})

N = 788.6 Newton

N = 789 Newton

So, the normal force exerted by the seat of the car is 789 Newton.

6 0
3 years ago
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