M = mass of the first sphere = 10 kg
m = mass of the second sphere = 8 kg
V = initial velocity of the first sphere before collision = 10 m/s
v = initial velocity of the second sphere before collision = 0 m/s
V' = final velocity of the first sphere after collision = ?
v' = final velocity of the second sphere after collision = 4 m/s
using conservation of momentum
M V + m v = M V' + m v'
(10) (10) + (8) (0) = (10) V' + (8) (4)
100 = (10) V' + 32
(10) V' = 68
V' = 6.8 m/s
Gradpoint ? And the answer is water.
Answer:
the answer is C i didnt mean to put b lol
Explanation:
Answer:
P = 1235.7646 W
Explanation:
Given data:
height of raised sewage = 5.49 m
rate of sewage =1.89*10^6 lt/day
density of sewage = 1.050 kg/m^3
power is written as
work = m g h
h -height
mass lifted per day 
= 1984500 kg
time = 24 hours* 3600 seconds per hour
power
P = 1235.7646 W
Answer:
2.42hours
Explanation:
To calculate the time taken to boil the cup of water, we will use the formula
Q = It where
Q is the total energy required to boil the water = 100KJ = 100,000Joules
I is the current = 11.5A
t is the time taken to boil the water
t = Q/I
t = 100,000/11.5
t = 8695.65seconds
t = 2.42hours
