The equation for electrical power is<span>P=VI</span>where V is the voltage and I is the current. This can be rearranged to solve for I in 6(a).
6(b) can be solved with Ohm's Law<span>V=IR</span>or if you'd like, from power, after substituting Ohm's law in for I<span>P=<span><span>V2</span>R</span></span>
For 7, realize that because they are in parallel, their voltages are the same.
We can find the resistance of each lamp from<span>P=<span><span>V2</span>R</span></span>Then the equivalent resistance as<span><span>1<span>R∗</span></span>=<span>1<span>R1</span></span>+<span>1<span>R2</span></span></span>Then the total power as<span><span>Pt</span>=<span><span>V2</span><span>R∗</span></span></span>However, this will reveal that (with a bit of algebra)<span><span>Pt</span>=<span>P1</span>+<span>P2</span></span>
For 8, again the resistance can be found as<span>P=<span><span>V2</span>R</span></span>The energy usage is simply<span><span>E=P⋅t</span></span>
Answer:
Multiple so you can test multiple hypothesis at once
Explanation:
because
Energy/power is not gained or lost going through a (ideal) transformer.
So the transformer in this problem really doesn't matter. If the lamp is using energy at the rate of 60 watts, then the whole contraption is getting 60 watts of power from the wall outlet.
Power = (voltage) x (current)
60 watts = (120 v) x (current)
Current = (60 watts) / (120 v)
<em>Current = 0.5 Ampere</em>
The displacement of Edward in the westerly direction is determined as 180.27 km.
<h3>Displacement of Edward</h3>
The displacement of Edward is calculated as follows;
R² = a² + b² - 2abcosθ
R² = 150² + 200² - 2(150 x 200) x cos60
R² = 32500
R = 180.27 km
Thus, the displacement of Edward in the westerly direction is determined as 180.27 km.
Learn more about displacement here: brainly.com/question/321442
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