Let X be the first number
there is a 2 numbers distance between each even number eg.2 ,4, 6, 8, etc.
So the 2nd number is X+2
The sum of the 1st and 2nd numbers = 14
X + X+2 =14
2X +2 =14
2X = 14-2
2X = 12
X = 12/2
X = 6
Therefore,
The first number i.e, X = 6
And the second number i.e, X+2 = 6+2 =8
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This is the only positive pair in case of two consecutive numbers if the are even numbers but not consecutive there will be more pairs
12 + 2 = 14
10 + 4 = 14
8 + 6 = 14 (Already found)
Answer:
HK = 20
Step-by-step explanation:
LM = (1/2) HK {Mid point theorem}
2*(10x - 90) = 10x - 80
2*10x - 2*90 = 10x - 80
20x - 180 = 10x - 80 {add 180 to both sides}
20x = 10x - 80 + 180
20x = 10x +100 {Subtract 10x from both sides from }
20x -10x = 100
10x = 100
x = 100/10
x = 10
HK = 10x - 80
= 10*10 - 80
= 100 - 80
= 20
Answer:
1843:6754.9709254546.,657675
Step-by-step explanation:
Divide by a whole number to get 40 which is 5 and then keep left over 3/8 to get mixed number of 5 3/8
