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3 years ago

12

What is x to the nearest tenth? Show work pls.

1 answer:

FromTheMoon [43]3 years ago

3 0

No i cannot do that i am very sorry i need point

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What's the answer a or b

Yakvenalex [24]

The answer is b hope this helps

4 0

4 years ago

a car travelling a constant speed of 60km in 18 minutes .how far will the car travel in 1 hour 12 minutes?

Alexandra [31]

Answer:

240 km.

Step-by-step explanation:

The car travels 200km per hour. so multiply it by 1.2 and you get 240km.

7 0

3 years ago

The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s

Zielflug [23.3K]

Answer:

The lengths of sides of squares are 5 cm and 9 cm.

Step-by-step explanation:

Let the sides of rectangle be x and y .

Area of rectangle = Length × Breadth

Given : Area of rectangle = 45 cm².

⇒ x × y = 45

⇒ $x=\frac{45}{y}$ ........(1)

Two squares are constructed such that two adjacent sides of the rectangle

so squares have side x and y .

Area of square = side × side

Area of square with side x = x²

Area of square with side y = y²

Also, The combined area of the two squares is 106 cm².

⇒ x² + y² = 106

From (1) put value of x , we get,

$(\frac{45}{y})^2+y^2=106$

Solving for y ,

$(\frac{45}{y})^2+y^2=106$

$2025+y^4=106y^2$

$y^4-106y^2+2025=0$

$y^4-81y^2-25y^2+2025=0$

$y^2(y^2-81)-25(y^2-81)=0$

$(y^2-25)(y^2-81)=0$

$y^2-81=0$ or $y^2-25=0$

on solving we get y = 5 and y = 9

Also, x can be find by putting in (1),

⇒ $x=\frac{45}{5}=9$ and ⇒ $x=\frac{45}{9}=5$

⇒ x = 9 and x = 5

Thus, lengths of sides of squares are 5 cm and 9 cm.

6 0

3 years ago

Read 2 more answers

Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

<u><em>Applying the law of sines in the right triangle BDC</em></u>

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

<u><em>Applying the law of sines in the right triangle ABC</em></u>

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$

<u><em>Find the value of BC</em></u>

$BC=(sin(70\°))\frac{6.6}{sin(20\°)}$

$BC=18.12\ m$

therefore

The height of the tree is 18.12 m

5 0

4 years ago

Can u plsss help me out with this thanks

alex41 [277]

Number 3 is x=3 Number 5 is x=-1 Number 7 is x=9 Number 9 is x=10

8 0

3 years ago

Read 2 more answers