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Svet_ta [14]
3 years ago
14

What is the energy needed to raise an electron in the hydrogen atom from the second energy level to the third energy level ?

Chemistry
1 answer:
nignag [31]3 years ago
5 0
\Delta E=|E_{2}-E_{3}|=|\frac{E_{1}}{4}-\frac{E_{1}}{9}|=|\frac{-13.9eV}{4}-\frac{-13.9eV}{9}|=\\\\
=|-3.475eV+1.544eV|=|-1,931eV|=1.931eV

 1eV --------- is ----------- 1.6*10⁻¹⁹J
1.931eV ---- is -----------  x

x = [1.931eV*1.6*10⁻¹⁹J]/1eV ≈ 3,1*10⁻¹⁹J

<u>ANSWER E</u>
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Answer:

shorter than

equal to

Explanation:

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KE = E - Wo

Where

KE = kinetic energy of the photoelectron

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Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.

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Where;

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m = mass

v = velocity

Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.

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8 0
3 years ago
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Answer:

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Explanation:

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Explanation :

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According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

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Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

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