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2 years ago

Parents should avoid sharing their own mistakes with children. True/false

Chemistry

2 answers:

Vesna [10]2 years ago

6 0

Parents SHOULDN'T avoid sharing their own mistakes with children.

Drupady [299]2 years ago

4 0

False because if a parent share their own mistakes then the children can avoid the mistake the parents made

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Which of the following reactions would you find in a radioisotope thermal generator

slavikrds [6]

The answer to your question is option 1. I hope this has helped.

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3 years ago

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3. What are the products of the following reaction?

aev [14]

B is the right answer because it’s a double replacement reaction and the potassium is balanced with the sulphate

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2 years ago

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John rode 3150 m at an average speed of 350 m/min.If he had ridden at average of 375 m/min instead. How much sooner would it hav

Svet_ta [14]

Explanation:

Given that:

Distance traveled = 3150m

Average speed = 350m/min

Suggested speed = 375m/min

Unknown:

Time = ?

Solution:

Speed is the rate of change of distance with time.

it is mathematically expressed as;

speed = $\frac{distance }{time}$

Initial time using speed 350m/min can be calculated by making time the subject of the formula;

time taken = $\frac{distance }{speed}$

time taken at speed of speed of 350m/min = $\frac{3150}{350}$ = 9min

to seconds = 9 x 60 = 540 seconds

time taken at speed of 375m/min = $\frac{3150}{375}$ = 8.4min

to seconds = 8.4 x 60 = 504 seconds.

It could have taken 504 seconds sooner saving 36 seconds.

learn more:

Speed brainly.com/question/10177389

#learnwithBrainly

7 0

3 years ago

Elements in the same period have _____.

faust18 [17]

Ans: Elements in the same period have the same number of electron shells.

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2 years ago

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Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

4 0

2 years ago