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2 years ago

Parents should avoid sharing their own mistakes with children. True/false

Chemistry

2 answers:

Vesna [10]2 years ago

6 0

Parents SHOULDN'T avoid sharing their own mistakes with children.

Drupady [299]2 years ago

4 0

False because if a parent share their own mistakes then the children can avoid the mistake the parents made

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How many milliliters are in 22 mm3?

AURORKA [14]

Fuf9chlbcoc cpchchlccpj hl hl hlxypcoyohcohchho. lh ohcgl vk .

8 0

2 years ago

A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab

77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

By definition, $pH = -log[H_3O^+]$ .
NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: $NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq)$ .
From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: $[NaOH] = [OH^-]$ .
Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: $[OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}$ .
We also know that $pOH = 14.00 - pH = -log[NaOH]$ . Take the antilog of both sides: $10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}$ .
Solve for the mass of NaOH: $m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V$ .

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

$m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g$

7 0

2 years ago

For the imine synthesis reaction, the two reactants react in melting state. How is that possible since the melting points for bo

pychu [463]

Answer:

I have no clue at all im in 11 and dont know anything lol byeeee

Explanation:um um i am lost

7 0

2 years ago

Use the normal boiling points: propane, C3H8, –42.1˚C; butane, C4H10, –0.5˚C; pentane, C5H12, 36.1˚C; hexane, C6H14, 68.7˚C; hep

svlad2 [7]

Answer:

The answer to your question is 126.1°C

Explanation:

Boiling point Difference of boiling points

C₃H₈ - 42.1°C

C₄H₁₀ - 0.5°C 41.6 °C

C₅H₁₂ 36.1°C 36.6°C 41.6 - 36.6 = 5°C

C₆H₁₄ 68.7°C 32.6°C 36.6 - 32.6 =4°C

C₇H₁₆ 98.4°C 29.7°C 32.6 - 29.7 = 2.9°C

We can observe on the table that the difference of boiling points diminishes 1°C when the hydrocarbon has one more carbon, then the difference of temperature between the hydrocarbon of 8 carbons and the hydrocarbon of 7 carbons must be 2°C.

So, this difference is 29.7°C - 2°C = 27.7°C.

And the boiling point of octane is approximately 98.4 + 27.7°C = 126.1°C

7 0

2 years ago

Identify the missing coefficient in the following equation: 3 2 1 0

Pie

Answer:

Explanation:

In balancing nuclear reactions the mass number and atomic numbers are usually conserved. This implies that from the given equation, the sum of the number of the subscript on the right hand side must be equal to that on the left hand side. This also applies to the superscript:

For the mass numbers(superscript):

235 + 1 = 1 + 139 + 95

236 = 235

This is not balanced

For the atomic number:

92 + 0 = 0 + 53 + 39

92 = 92

This is balanced.

We simply inspect to see how to balance the mass number.

By putting a coefficient of 2 behind the neutron atom, the equation becomes balanced.

7 0

3 years ago