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Zielflug [23.3K]
3 years ago
7

What is a closed system in chemistry? What is an open system in chemistry? plzz dont make the answer too smart so dumb it down a

lil. ​
Chemistry
1 answer:
kondaur [170]3 years ago
5 0

Answer:

A open system is a system that exchanges energy and matter with its surroundings.

A closed system is a system that exchanges energy only with its surroundings, not matter.

-----------

hopefully my answer helps! ♡

if my answers helped you please tell me, therefore I know.. that I did them correctly or incorrectly. anyways, have a great day/night!

You might be interested in
1. In this experiment, the procedure instructs you to dissolve solid potassium hydrogen tartrate (KHT) in two different solvents
GuDViN [60]

Answer:

Water

Explanation:

Solid potassium hydrogen tartrates (KHT) is soluble in water. This is especially at room temperature.

The solvent for KHT is water.

3 0
3 years ago
Calculate the pHpH of a 0.10 MM solution of HClHCl . Express your answer numerically using two decimal places.
alisha [4.7K]

Answer: The pH 0f 0.10 solution of HCl is 1.00

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,  

1 mole of HCl gives 1 mole of H^+  

Thus 0.10 moles of HCl gives =\frac{1}{1}\times 0.10=0.10 moles of H^+  

Putting in the values:

pH=-\log[0.10]

pH=1.00

Thus pH 0f 0.10 solution of HCl is 1.00

8 0
3 years ago
Please help , science tho. by the way i have to do 5
kap26 [50]

Answer:

850

Explanation:

It's between 840 and 860

8 0
2 years ago
What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig
Mashutka [201]

Answer:

P_H =2.86

c=1.4\times 10^{-4}

Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

K_a =1.38\times10^{-4}

\alpha = \frac{1}{10}

P_H= 3.86-1

P_H =2.86

composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

c=1.4\times 10^{-4}

6 0
3 years ago
Why does ionization energy tend to increase as you move across a period
koban [17]
It tends to in increase because the size of the atoms increase. 
4 0
3 years ago
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