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4 years ago

The proof that ch4 is a weak acid

Chemistry

2 answers:

boyakko [2]4 years ago

8 0

Answer: because ch4 is not considered a acid they said it is too weak

Explanation:

Paha777 [63]4 years ago

6 0

Ch4 isnt even an acid

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Which of the following elements has the largest atomic radius? (2 points) Silicon Aluminum Sulfur Phosphorous

amm1812

as you move in the periodic table from left to right he atomic radius decreases...

this is how they are avenged in periodic table, now you can answer which is having smaller radius and also which has larger radius

Al Si P S

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3 years ago

Read 2 more answers

BRAINLIEST AND 30 POINTS! concept map for four types of intermolecular forces and a certain type of bond is shown.

Sphinxa [80]

D represents ion-dipole forces that are stronger than the force C.

Explanation:

D represents the ion-dipole force.

C represents the H-bonding forces.

ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.

It is electrostatic in nature.

A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N

Ion dipole force is stronger than the H-bonding.

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3 years ago

Entalpy of vaporization of water is 41.1k/mol. if the vapor pressure of water at 373k is 101.3 kpa, what is the vapor pressure o

allsm [11]

Answer: The vapor pressure of water at 298 K is 3.565kPa.

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = initial pressure at 298 K = ?

$P_2$ = final pressure at 373 K = 101.3 kPa

$\Delta H_{vap}$ = enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 298 K

$T_2$ = final temperature = 373 K

Now put all the given values in this formula, we get

$\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]$

$\frac{101.3}{P_1}=antilog(1.448)$

$P_1=3.565kPa$

Therefore, the vapor pressure of water at 298 K is 3.565kPa.

3 0

4 years ago

Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.

kumpel [21]

Answer : The limiting reactant is $O_2$

Explanation : Given,

Mass of $C_3H_8$ = 30.0 g

Mass of $O_2$ = 75.0 g

Molar mass of $C_3H_8$ = 44 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_3H_8$ and $O_2$ .

$\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{30.0g}{44g/mole}=0.682moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{75.0g}{32g/mole}=2.34moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

From the balanced reaction we conclude that

As, 5 mole of $O_2$ react with 1 mole of $C_3H_8$

So, 2.34 moles of $O_2$ react with $\frac{2.34}{5}\times 1=0.468$ moles of $C_3H_8$

From this we conclude that, $C_3H_8$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Therefore, the limiting reactant is $O_2$

5 0

3 years ago

A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla

mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times }{V_s}$