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3 years ago

What is the relationship between the ratios? 4872 and 69 Drag and drop to complete the statement.

Mathematics

2 answers:

Darya [45]3 years ago

8 0

the answer is proportional

i took this test already

goldfiish [28.3K]3 years ago

4 0

The answer is Not Proportional. I have this test too. Hope it helps!

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h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

6 0

3 years ago

R --> 2 P. Initially you start off with 0.5 M reactants and let the reaction run to equilibrium and calculate the equilibrium

Anit [1.1K]

Answer:

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

$\frac{C^{c}D^{d} }{A^{a}B^{b} }$

K is a constant so it won't change the value. Instead, the values of C and D are going to change. The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

8 0

3 years ago

Three items weighing 5.28 kg 3.68 kg and 5.49 kg are to be posted but are found to be overweight. By how much does the total wei

NikAS [45]

Answer:

1.69 kg

Step-by-step explanation:

add than subtract

yep thats it

3 0

3 years ago

Please help this is due and i only got the second part done

Ainat [17]

Answer:2n+13=75 n=31

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3 years ago

It says it in the image please help me

r-ruslan [8.4K]

Answer:

The answer you have selected should be correct.

6 0

3 years ago