Answer:
look at the graph i made with desmos, i just plugged the equation in.
Step-by-step explanation:
On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-interc
2 answers:
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Answer:
Unit rates for cyclist A , B, C , D are 12 mile/ hour , 5 mile/hour, 9 mile/hour and 10 mile/hour respectively. Cyclist A is the fastest among the four.
Step-by-step explanation:
Cyclist A can ride 24 miles in 2 hours
so, cyclist A's unit rate is,
= 12 mile/hour
Cyclist B's unit rate is,
=
=
= 5 mile/hour
Equation for cyclist C is, y = 9x ,
so, cyclist C's unit rate is , 9 mile/hour
Slope of the graph for cyclist D,
=
= 10
So cyclist D's unit rate is, 10 mile/hour
So, cyclist A is the fastest.
Answer:
a) 0.057
b) 0.5234
c) 0.4766
Step-by-step explanation:
a)
To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula
where
N = size of the sample.
So,
As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.
We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.
So the p-value is
b)
Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.
We can compute the probability of such an error following the next steps:
<u>Step 1 </u>
Compute
So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.
<u>Step 2</u>
Compute the probability that your sample mean is less than 185.3711
So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>
c)
<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is
1 - 0.5234 = 0.4766