What net force would be needed to accelerate and object with a mass of 2kg to 100m/s?

The distance between two crests of a wave is called

Papessa [141]

The distance between two successive high points in a wave is called a wavelength

8 0

3 years ago

An office heater puts out 2090 Btu (British thermal units) of energy in the form of heat per hour. Given that 1 Btu=1.055 kJ, ho

lesya692 [45]

Answer:

Total energy produced 19135.362 MJ/year

Explanation:

given details:

total energy produced = 2090 Btu per hour

1 Btu = 1.055kJ

Total energy produced per year in mega joule is = 2090*1.055 *365*24

= 19315362 KJ/year

In mega joule per year $= \frac{19315362}{1000}$

mega joule per year = 19135.362 MJ/year

5 0

3 years ago

a 1000kg car uses a breaking force of 10,000N to stop in two second. What is the change in momentum of the car?

gayaneshka [121]

Answer:

ΔP = 20000 N s

Explanation:

To solve this problem we use the relation between momentum and moment

I = Δp

let's calculate the momentum

I = ∫F dt

if we use the average force

I = F t

I = 10000 2

I = 20000 N s

therefore with the first equation

ΔP = I = 20000 N s

8 0

3 years ago

A cannon of mass 5.71 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7

zheka24 [161]

Answer:

541.14 m/s

Explanation:

We are given that

Mass of cannon= $m_1=5.71\times 10^3 kg$

Mass of shell, $m_2=73.5 kg$

Initial velocity of shell,v=547 m/s

We have to find the velocity of shell fired from this loose cannon.

According to law of conservation of momentum

$m_1v_1+m_2v_2=m_1u_1+m_2u_2$

Initial momentum of system=0

$m_1v_1=-m_2v_2$

$v_1=-\frac{m_2v_2}{m_1}$

When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell

Kinetic energy of shell, $K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 73.5(547)^2}=1.09\times 10^7 J$

K.E of shell= $\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2$

K.E of shell= $\frac{1}{2}m_1(-\frac{m_2v_2}{m_1})^2+\frac{1}{2}m_2v^2_2$

K.E of shell= $\frac{1}{2}(\frac{m^2_2v^2_2}{m_1}+\frac{1}{2}m_2v^2_2)$

2K.E of shell= $m_2v^2_2(\frac{m_2}{m_1}+1)$

Velocity of shell fired from this loose cannon,v_2= $\sqrt{\frac{2k.E}{m_2(\frac{m_2}{m_1}+1)}$

$v_2=\sqrt{\frac{2\times 1.09\times 10^7}{73.5(\frac{73.5}{5.71\times 10^3}+1)}$

$v_2=541.14m/s$

Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s

5 0

3 years ago

What causes a bolt of lightning?

padilas [110]

The answer would be C. Lightning occurs when the negative charges from clouds attract towards the positive charges on the ground. These two charges attract and cause the spark of lightning. Hope this helps.

3 0

3 years ago

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