Answer:
33.33 seconds
Explanation:
= Initial length pulled = 20 cm
b = Damping constant = 0.015 kg/s
k = Spring constant = 4 N/m
m = Mass of glider = 250 g
Time period is given by
Using exponential decay formula
Final amplitude = Initial times decay
The time taken is 33.33 seconds
Answer:
The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.
Explanation:
Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively
and the mass of big rock be 'M'
Initial momentum of the system equals
Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'
Thus the final momentum of the system is
Equating initial and the final momenta we get
Now since the surface is frictionless thus the energy is also conserved thus
Similarly the final energy becomes
\
Equating initial and final energies we get
Solving i and ii we get
Using this in equation i we get
Thus putting v = -v' in equation i we get V' = 0
This implies Smaller stone rebounds while as larger stone remains stationary.
The first energy level can be occupied by a maximum of 2 electrons.
Each hydrogen atom has only one electron which occupies the first energy level.
Therefore, two hydrogen atoms will each share this one electron and form a covalent bond. By doing this (sharing electron), each of the two atoms will now be having 2 electrons (its original electron + the shared one from the other atom) and are now both stable forming a hydrogen molecule.