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xxMikexx [17]
3 years ago
7

I need to know the answer to this problem​

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

y^56

Step-by-step explanation:

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jenyasd209 [6]
7•5=35
7070-35=7035
f=7035
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3 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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3 years ago
7 less than the product of 5 and a number
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are there multiple choice answers because i can help with those.

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4 years ago
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Answer:

Step-by-step explanation:

8 0
3 years ago
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