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djyliett [7]
2 years ago
8

Will give 50 points

Mathematics
1 answer:
mafiozo [28]2 years ago
7 0

Answer:

120.96$

Step-by-step explanation:

150$ - 25% = 112$


112$ + 8% = 120.96$


Hope this helps!!

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Find the minimum sample size necessary to be 99% confident that the population mean is within 3 units of the sample mean given t
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Answer:

The minimum sample size required is 207.

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

The margin of error of this confidence interval is:

MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

Given:

MOE=3\\\sigma=29\\z_{\alpha /2}=z_{0.01/2}=z_{0.05}=2.576

*Use a <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=2.576\times \frac{29}{\sqrt{n}} \\n=[\frac{2.576\times29}{3} ]^{2}\\=206.69\\\approx207

Thus, the minimum sample size required is 207.

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