Answer: The empirical formula is 
Explanation:
Mass of Pb = 4.33 g
Mass of O = (5.00-4.33) g = 0.67 g
Step 1 : convert given masses into moles
Moles of Pb =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Pb = 
For O = 
The ratio of Pb O= 1: 2
Hence the empirical formula is
One way is studying through a satelite in space already.
Answer:
The chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.
Explanation:
Chemical equation:
Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)
Balanced chemical equation:
Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)
This equation showed that the chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.
Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.
The given equation is balanced and completely hold the law of conservation of mass.
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Answer:
1.84 g/cm³
Explanation:
A flask has a mass of 78.23 g when empty and 593.63 g when filled with water. The mass of water is:
m(water) = 593.63 g - 78.23 g = 515.4 g
The density of water is 1.00 g/cm³. The volume of water (and the flask) is:
515.4 g × (1 cm³/1.00 g) = 515 cm³
When the same flask is filled with concentrated sulfuric acid, H₂SO₄, its mass is 1026.57 g. The mass of H₂SO₄ is:
m(H₂SO₄) = 1026.57 g - 78.23 g = 948.34 g
948.34 g of sulfuric acid occupy a volume of 515 cm³. The density of sulfuric acid is:
ρ = 948.34 g / 515 cm³ = 1.84 g/cm³
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
Explanation:
Balanced chemical equation for combustion of pentane C₅H₁₀:
C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)
to get integer numbers for the stoechiometric coefficients we multiply with 2:
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
where:
(l) - liquid
(g) - gas
Learn more about:
combustion of hydrocarbons
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