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mezya [45]
3 years ago
11

What is the percentage of water in hydrated calcium chloride​

Chemistry
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

24.5%

Explanation:

You just add up the atomic masses.  

Ca - 40.078  

Cl2 - 35.4527 x 2 = 70.9054  

------ 110.9834  

H4 - 1.00794 x 4 = 4.03176  

O2 - 31.9998  

------ 36.03056  

TOTAL - 147.01396  

So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%

This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.

oee [108]3 years ago
8 0

Answer: <u>24.5%</u>

Explanation: Molar mass of CaCl2 * 2 H2O = 40.078 + ( 2 x 35.453) + ( 2 x 18.02)=147.024 g/mol  

% H2O = 2 x 18.02 x 100/ 147.024 =24.5

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You bought a new car and estimated that your monthly payment would be $312. However, your actual payment amount was $325. How mu
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Answer:

The error would be $13.

Explanation:

Given data:

Actual payment = $325

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Error =  Estimated payment - Actual payment

Error = $312  -  $325

Error = -$13

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4 years ago
The mass of 100cm3 of water is 100 g. Use the formula to calculate its density.
yanalaym [24]

Answer:

It should be 1 g/cm3. Hope this helpd!

4 0
3 years ago
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Name the following <br> Cr(SO4)2
inessss [21]
Chromium sulfate.
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3 0
3 years ago
The mass number for an atom is numerically equal to which quantity
Misha Larkins [42]

Answer:

The mass number of an atom is equal to the number of protons plus the number of neutrons that it contains. In other words, the number of neutrons in an atom is its mass number minus its atomic number.

Explanation:

protons

The mass number of an atom is its total number of protons and neutrons. Atoms of different elements usually have different mass numbers , but they can be the same. For example, the mass number of argon atoms and calcium atoms can both be 40.

4 0
3 years ago
Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of
pantera1 [17]

Answer:

W=5743.1077\ J

Explanation:

The expression for the work done is:

W=RT \ln \left( \dfrac{P_1}{P_2} \right)

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)

W=300\times \:8.314\ln \left(10\right)

W=2.30258\times \:2494.2

W=5743.1077\ J

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3 years ago
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