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mezya [45]
3 years ago
11

What is the percentage of water in hydrated calcium chloride​

Chemistry
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

24.5%

Explanation:

You just add up the atomic masses.  

Ca - 40.078  

Cl2 - 35.4527 x 2 = 70.9054  

------ 110.9834  

H4 - 1.00794 x 4 = 4.03176  

O2 - 31.9998  

------ 36.03056  

TOTAL - 147.01396  

So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%

This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.

oee [108]3 years ago
8 0

Answer: <u>24.5%</u>

Explanation: Molar mass of CaCl2 * 2 H2O = 40.078 + ( 2 x 35.453) + ( 2 x 18.02)=147.024 g/mol  

% H2O = 2 x 18.02 x 100/ 147.024 =24.5

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Calculate the number of grams of Mg needed for this reaction to release enough energy to increase the temperature of 78 mL of wa
Vaselesa [24]

Answer:

We need 1.1 grams of Mg

Explanation:

Step 1: Data given

Volume of water = 78 mL

Initial temperature = 29 °C

Final temperature = 78 °C

The standard heats of formation

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Step 2: The equation

The heat is produced by the following reaction:

Mg(s)+2H2O(l)→Mg(OH)2(s)+H2(g)

Step 3: Calculate the mass of Mg needed

Using the standard heats of formation:

−285.8 kJ/mol H2O(l)

−924.54 kJ/mol Mg(OH)2(s)

Mg(s) + 2 H2O(l) → Mg(OH)2(s) + H2(g)

−924.54 kJ − (2 * −285.8 kJ) = −352.94 kJ/mol Mg

(4.184 J/g·°C) * (78 g) * (78 - 29)°C = 15991.248 J required

(15991.248 J) / (352940 J/mol Mg) * (24.3 g Mg/mol) = 1.1 g Mg

We need 1.1 grams of Mg

7 0
3 years ago
Draw the reactants using the drawing tool. Keep in mind that one molecule of nitrogen has two bonded atoms, and one molecule of
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The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:

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<h3>What is the equation of the formation of ammonia?</h3>

Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.

Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.

The equation of the reaction is given below as:

N_2 + 3H_2 \rightarrow 2NH_3

Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.

Learn more about ammonia gas at: brainly.com/question/7982628

5 0
2 years ago
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Andrei [34K]

Answer:

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3 years ago
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PSYCHO15rus [73]

Answer:

After the solution is heated, but before additional solute is added

Explanation:

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