Cu + AgNO3 = Cu(NO3)2 +Ag

1 answer:

6 0

The problem is that you have to balance Cu + AgNO3 = Cu(NO3)2 + Ag

The first step is to identify all the elements and how many atoms of that element there are on either side of the equals sign.
When you do this you will get,

1 Cu 1
1 Ag 1
1 N 2
3 O 6

Next step is to make sure that all the elements are the same on both sides. This is mostly trial and error until you balance both sides.

The solution to the equation would be:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

So now if you check your elements, you will get the following:

1 Cu 1
2 Ag 2
2 N 2
6 O 6

As you can see all the elements are equal on both sides, so the equation is balanced.

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Do you think the tectonic plates are still moving today?why?

jek_recluse [69]

Yes, The tectonic plates are always moving and interacting today. The continents are still moving today. Because sometimes of the most dynamic sites of tectonic activity are seafloor spreading zones and giant rift valleys.

3 0

2 years ago

Consider this equilibrium reaction between carbon monoxide and hydrogen gas, occurring in a sealed flexible container. CO(g) + 3

wariber [46]

Answer:

More H2(g) is added to the container : Towards products.

CO is removed from the container : Towards reactants.

More CH4(g) is added to the container : Towards reactants

H2O(g) is removed from the container : Towards products.

The contents of the container are heated up. : Towards the reactants.

The contents of the container are cooled down : Towards the products.

The pressure inside the container is increased. :Towards the products

The container is stretched to increase the volume: Towards the reactants.

Explanation: :

CO(g) + 3 H2g) → CH4(g) + H2O(g)+ heat

There is released heat, so this reaction is exothermic

If the H2 concentration is increased, the system will try to change the concentration change by shifting the balance to the right, and thus the concentration of products will increase. Towards products.

If the CO is removed, the system will try to change this situation by shifting the balance to the left, and thus the concentration of reactants will increase, the concentration of products will decrease. Towards reactants.

If the CH4 concentration is increased, the system will try to change the concentration change by shifting the balance to the left, and thus the concentration of reactants will increase. Towards reactants

If the H2O is removed, the system will try to change this situation by shifting the balance to the right, and thus the concentration of products will increase, the concentration of products will decrease. Towards products.

If the temperature is increased, the system will reduce the amount of heat released. So the balance will shift to the left. Towards the reactants.

This because the extra heat / energy must be used.

If the temperature is decreased, the system will produce more heat So the balance will shift to the right. Towards the products.

This because more heat /energy needs to be produced to make up for the loss of heat (energy).

If the pressure is increased, the system will shift to the side with fewer moles of gas. In this case, there are 4 moles on the left and 2 moles on the right. So the balance will shift to the right. Towards the products. An increase of pressure has the same effect on the equilibrium as a decrease of the volume.

If the volume is increased, this means the pressure is decreased, the system will shift to the side with most moles of gas. In this case, there are 4 moles on the left and 2 moles on the right. So the balance will shift to the left. Towards the reactants. An increase of volume has the same effect on the equilibrium as a decrease of the pressure.

6 0

3 years ago

Which of the following alkyl halides will react fastest with CH3OH in an SN1 mechanism?

yaroslaw [1]

Answer:

Explanation:

The complete question is shown in the image attached.

Let us call to mind the fact that the SN1 mechanism involves the formation of carbocation in the rate determining step. The order of stability of cabocations is; tertiary > secondary > primary > methyl.

Hence, a tertiary alkyl halide is more likely to undergo nucleophilic substitution reaction by SN1 mechanism since it forms a more stable cabocation in the rate determining step.

Structure IV is a tertiary alkyl halide, hence it is more likely to undergo nucleophilic substitution reaction by SN1 mechanism.