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4 years ago

If y varies directly as x and y is 400 when x is r when x is 4 what is the numeric constant of variation in this relation

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

8 0

Answer: y is 100 times what x is.

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27 divided by 53 minus 6 plus 53 times -2 squared

mamaluj [8]

Answer:

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Step-by-step explanation:

Considering the expression

27 divided by 53 minus 6 plus 53 times -2 squared

Which can be written as

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

So, solving the expression

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{27}{53}-6-53\cdot \:2^2$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:6=\frac{6\cdot \:53}{53}$

$=-\frac{6\cdot \:53}{53}+\frac{27}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-6\cdot \:53+27}{53}$

$=\frac{-291}{53}$ ∵ $-6\cdot \:53+27=-291$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-2^2\cdot \:53-\frac{291}{53}$

$=-212-\frac{291}{53}$ ∵ $53\cdot \:2^2=212$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:212=\frac{212\cdot \:53}{53}$

$=-\frac{212\cdot \:53}{53}-\frac{291}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-212\cdot \:53-291}{53}$

$=\frac{-11527}{53}$ ∵ $-212\cdot \:53-291=-11527$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{11527}{53}$

Therefore,

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Keywords: algebraic expression

Learn more about solving algebraic expression from brainly.com/question/4687406

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8 0

4 years ago

Question 4 (4 points

aalyn [17]

Answer:

It is True 200% legit!

Step-by-step explanation:

4 0

3 years ago

Ifangle1∠ 1 and angle2∠ 2 are complementary, find the measure of x and the measures of the angles when LaTeX: m\angle1=\left(6x+

Liono4ka [1.6K]

Answer:

Step-by-step explanation:

The sum of two complementary angle is 90 degrees. Given the following complementary angles;

<1 = 6x + 5

<2 = 8x + 15

<1 + <2 = 90 (complementary angles)

6x + 5 + 8x + 15 = 90

14x + 20 = 90

14x = 90-20

14x = 70

x = 70/14

x = 5

Hence the measure of x is 5

6 0

3 years ago

Plz help me understand

faltersainse [42]

So what I have gotten from this is the dates 1 Jan -8 Jan they where gone 7 days so look at the prices of the per night I hope it helps

5 0

4 years ago

Due this Thursday.. help pls.

kobusy [5.1K]

2004 was a leap year so 29/366=7.9%

4 0

3 years ago