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oksano4ka [1.4K]
3 years ago
5

Evaluate: -9 + 25 - (-10) + (-6)

Mathematics
2 answers:
Paul [167]3 years ago
6 0

Answer:

     e2valut + 20

Step-by-step explanation:

Please make mine the brainliest

Minchanka [31]3 years ago
4 0
-9 is a negative number, so plus 25, it would be 16. The minus sign and the negative sign of -10 cancel out, so it is plus 10, ending up with 26. Finally, the + and - becomes negative (positive times negative equals negative), so it is -6 and you’ll end up with a final answer of 20.
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Answer:


use the verticle line test. if a verticle line touches two points on the graph then it is not a function, if the verticle line only touches one point then it is a function.

for your question the answer is the 3rd option - Graph with 5 points plotted at (negative 3, 2), (negative 2, negative 1), (0, 3), (1, 0), and (2, negative 3)


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What is the equation of the circle with center (−3, 1) that passes through the point (−5, 3)?
Mariulka [41]

Answer:

( x + 3)^2 + ( y - 1)^2 = 8

Step-by-step explanation:

The equation of a circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( x , y) - any point on the circle

( a, b) - center of the circle

r^2 - radius of the circle

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a = -3

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( -5 , 3) - point - ( x, y)

x = -5

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Step 1: substitute the center into the equation

( x -(-3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + ( y - 1)^2 = r^2

Step 2 : sub the point into the equation

( x + 3)^2 + ( y - 1)^2 = r^2

( -5 + 3)^2 + ( 3 - 1)^2 = r^2

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( x + 3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + (y - 1)^2 = 8

Therefore, the equation of the circle is

( x + 3)^2 + (y - 1)^2 = 8

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