This is an incomplete question, here is a complete question.
Consider the second-order decomposition of nitroysl chloride:
At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?
Answer : The time needed for NOCl is, 2.52 seconds.
Explanation : Given,
Rate constant =
Initial partial pressure of NOCl = 56 torr = 0.0737 atm
final partial pressure of NOCl = 14.5 torr = 0.0191 atm
The expression used for second order kinetics is:
where,
k = rate constant
t = time
= concentration at time 't'
= initial concentration
As we know that,
Thus, the expression of second order kinetics will be:
As,
So, ............(1)
Now put all the given values in the above expression 1, we get:
Therefore, the time needed for NOCl is, 2.52 seconds.
Answer:
I thinks it's c
Explanation:
cold air is denser than hot air so it sinks.
Answer: In a half-cell is where occurs the either oxidation (loss of electrons) or reduction (gain of electrons) but not both.
Explanation:
1) In an electrolitic cell you can identify two half-cells.
2) In one half-cell occurs the oxidation
3) In the other half-cell occurs the reduction.
4) The half-cell where oxidation occurs is the anode.
In the anode the spieces increase its oxidation number, which is what oxidation means. Increasing the oxidation number means that the spieces is losing electrons.
5) The half-cell where reduction occurs is the cathode.
Reduction is the reduction of the oxidation number and this occurs due to the gain of electrons.