All categories

3 years ago

What has law is in use when you place dry ice into a balloon

Chemistry

1 answer:

inn [45]3 years ago

4 0

Answer:

When dry ice is exposed to warm air, a gas called carbon dioxide is produced through a process called sublimation

Explanation:

You might be interested in

Please HELP will give Brainliest!!!!!

dedylja [7]

4 mol / 205g H2O = 4/.205 = 19.5 mol/kg boiling point = 100 + 19.5 • 0.51 = 109 ºC

7 0

3 years ago

A bond in which one atom contributes both bonding electrons to a covalentbond

yKpoI14uk [10]

<h3>Answer:</h3>

A coordinate bond

<h3>Explanation:</h3>

A chemical bond is a force of attraction between two or more atoms of elements.
Covalent bond is a type of chemical bond that occurs between non-metal atoms.
It occurs as a result of sharing of electrons between the non-metal atoms.
Atoms involved in covalent bond formation may contribute equally to the bond formation or the electrons shared may come form one of the atoms.
When the electrons shared in a covalent bond are derived from one atom, then the covalent bond is known as a coordinate bond.

4 0

3 years ago

Someone please answer i’ll give you brainly.

lina2011 [118]

Let's hope she didn't watch it without me or i will never be speaking to her again :))

4 0

2 years ago

On a coordinate plane, which single transformation could map point A (3,-4) onto point A' (1.5,-2)? *

Ksenya-84 [330]

Answer: A dilation with rule: $(x,y)\to(\dfrac12x,\dfrac12y)$

Explanation:

A dilation is a non-rigid transformation that creates an image that is the same shape as the original but has a different size.

It uses a scale factor k such that

$(x,y)\to(kx,ky)$

(x,y)= coordinates of original figure

(kx,ky) = corresponding coordinate in the image.

To transform: A (3,-4) onto point A' (1.5,-2).

Using scale factor k= $\dfrac12$ , we have

$A(3,-4)\to A'(\dfrac12\times3, \dfrac12\times-4)=A'(1.5,-2)$

Required rule: $(x,y)\to(\dfrac12x,\dfrac12y)$

3 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is

Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0

3 years ago